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Chapter 6 of 12
Flashcards

Permutations and Combinations

CBSE · Class 11 · Applied Mathematics

Flashcards for Permutations and Combinations — CBSE Class 11 Applied Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts
24 Flashcards
Card 1Factorial

What is factorial notation and how do you calculate n!?

Answer

Factorial notation n! (read as 'n factorial') is the product of first n natural numbers. n! = 1 × 2 × 3 × ... × (n-1) × n Special cases: 0! = 1, 1! = 1 Example: 5! = 1 × 2 × 3 × 4 × 5 = 120 Recursive

Card 2Fundamental Principles

State the Fundamental Principle of Addition (Rule of Sum)

Answer

If event E can occur in m ways and event F can occur in n ways (and both events cannot occur simultaneously), then either event E or F can occur in (m + n) ways. Example: If there are 3 physics books

Card 3Fundamental Principles

State the Fundamental Principle of Multiplication (Rule of Product)

Answer

If an event can occur in m different ways, and following this, another event can occur in n different ways, then the total number of ways both events can occur in succession is m × n. Example: If ther

Card 4Permutations

What is a permutation? Give the definition and an example.

Answer

A permutation is an arrangement of objects in a definite order, taking some or all objects at a time. Order matters in permutations. Example: The letters A, B, C can be arranged as ABC, ACB, BAC, BCA,

Card 5Permutations

What is the formula for permutations of n distinct objects taken r at a time without repetition?

Answer

ⁿPᵣ = n!/(n-r)! where n ≥ r ≥ 0 Alternatively: ⁿPᵣ = n(n-1)(n-2)...(n-r+1) Example: ⁵P₃ = 5!/(5-3)! = 5!/2! = 5×4×3 = 60 When r = n: ⁿPₙ = n!/0! = n!

Card 6Permutations

What is the formula for permutations with repetition allowed?

Answer

When repetition is allowed, the number of permutations of n distinct objects taken r at a time is: nʳ Example: How many 3-digit numbers can be formed using digits 1,2,3 with repetition? Answer: 3³ =

Card 7Permutations

Solve: How many 4-letter words can be formed using the letters of HONEST without repetition?

Answer

HONEST has 6 distinct letters. We need to arrange 4 letters from these 6. Using permutation formula: ⁶P₄ = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360 Therefore, 360 four-letter words can be formed.

Card 8Permutations

What is the formula for permutations of n objects where some objects are identical?

Answer

When n objects include p₁ objects of one kind, p₂ objects of second kind, ..., pₖ objects of kth kind: Formula: n!/(p₁! × p₂! × ... × pₖ!) Example: Letters of LETTER L-1, E-2, T-2, R-1 (total 6 lett

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Frequently Asked Questions

What are the important topics in Permutations and Combinations for CBSE Class 11 Applied Mathematics?

Permutations and Combinations covers several key topics that are frequently asked in CBSE Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 24 flashcards for Permutations and Combinations covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.