Permutations and Combinations
CBSE · Class 11 · Applied Mathematics
Flashcards for Permutations and Combinations — CBSE Class 11 Applied Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
What is factorial notation and how do you calculate n!?
Answer
Factorial notation n! (read as 'n factorial') is the product of first n natural numbers. n! = 1 × 2 × 3 × ... × (n-1) × n Special cases: 0! = 1, 1! = 1 Example: 5! = 1 × 2 × 3 × 4 × 5 = 120 Recursive
State the Fundamental Principle of Addition (Rule of Sum)
Answer
If event E can occur in m ways and event F can occur in n ways (and both events cannot occur simultaneously), then either event E or F can occur in (m + n) ways. Example: If there are 3 physics books
State the Fundamental Principle of Multiplication (Rule of Product)
Answer
If an event can occur in m different ways, and following this, another event can occur in n different ways, then the total number of ways both events can occur in succession is m × n. Example: If ther
What is a permutation? Give the definition and an example.
Answer
A permutation is an arrangement of objects in a definite order, taking some or all objects at a time. Order matters in permutations. Example: The letters A, B, C can be arranged as ABC, ACB, BAC, BCA,
What is the formula for permutations of n distinct objects taken r at a time without repetition?
Answer
ⁿPᵣ = n!/(n-r)! where n ≥ r ≥ 0 Alternatively: ⁿPᵣ = n(n-1)(n-2)...(n-r+1) Example: ⁵P₃ = 5!/(5-3)! = 5!/2! = 5×4×3 = 60 When r = n: ⁿPₙ = n!/0! = n!
What is the formula for permutations with repetition allowed?
Answer
When repetition is allowed, the number of permutations of n distinct objects taken r at a time is: nʳ Example: How many 3-digit numbers can be formed using digits 1,2,3 with repetition? Answer: 3³ =
Solve: How many 4-letter words can be formed using the letters of HONEST without repetition?
Answer
HONEST has 6 distinct letters. We need to arrange 4 letters from these 6. Using permutation formula: ⁶P₄ = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360 Therefore, 360 four-letter words can be formed.
What is the formula for permutations of n objects where some objects are identical?
Answer
When n objects include p₁ objects of one kind, p₂ objects of second kind, ..., pₖ objects of kth kind: Formula: n!/(p₁! × p₂! × ... × pₖ!) Example: Letters of LETTER L-1, E-2, T-2, R-1 (total 6 lett
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Permutations and Combinations covers several key topics that are frequently asked in CBSE Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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