Sequences and Series
CBSE · Class 11 · Applied Mathematics
Flashcards for Sequences and Series — CBSE Class 11 Applied Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
What is a sequence? Give an example.
Answer
A sequence is an ordered collection of numbers arranged according to a specific pattern or rule. Each number in the sequence is called a term. Example: 2, 4, 6, 8, 10, ... (even numbers) where a₁ = 2,
What is the difference between a sequence and a series?
Answer
A sequence is an ordered list of terms (e.g., 1, 3, 5, 7, ...), while a series is the sum of terms in a sequence (e.g., 1 + 3 + 5 + 7 + ...). If a₁, a₂, a₃, ... is a sequence, then a₁ + a₂ + a₃ + ...
Define Arithmetic Progression (AP) and give its general form.
Answer
An Arithmetic Progression is a sequence where each term (except the first) is obtained by adding a constant 'd' to the previous term. General form: a, a+d, a+2d, a+3d, ... where 'a' is the first term
State the formula for the nth term of an AP.
Answer
The nth term of an AP is: aₙ = a + (n-1)d, where 'a' is the first term, 'd' is the common difference, and 'n' is the term number. This formula helps find any term in the AP without calculating all pre
What is the sum of first n terms of an AP?
Answer
The sum of first n terms of an AP is: Sₙ = n/2[2a + (n-1)d] or Sₙ = n/2[a + l], where 'a' is the first term, 'd' is the common difference, 'l' is the last term, and 'n' is the number of terms.
Find the 15th term of the AP: 3, 7, 11, 15, ...
Answer
Given: a = 3, d = 7-3 = 4, n = 15 Using aₙ = a + (n-1)d a₁₅ = 3 + (15-1)×4 = 3 + 14×4 = 3 + 56 = 59 Therefore, the 15th term is 59.
What is Arithmetic Mean (AM)? How do you find AM of two numbers?
Answer
Arithmetic Mean is the average of numbers. For two numbers a and b, AM = (a+b)/2. If A is the AM of a and b, then a, A, b forms an AP. The AM is the middle term that makes the sequence arithmetic.
List three important properties of AP.
Answer
1. Adding a constant to each term: Results in AP with same common difference 2. Multiplying each term by a constant k: Results in AP with common difference = k×d 3. Equidistant terms property: In fini
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Sources & Official References
- NCERT Official — ncert.nic.in
- CBSE Academic — cbseacademic.nic.in
- CBSE Official — cbse.gov.in
- National Education Policy 2020 — education.gov.in
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