Application of Derivatives — Practice Questions
JEE Advanced · Mathematics
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Sample Questions
Find the slope of the tangent to the curve y = x³ - 3x + 2 at the point (2, 4).
The equation of normal to the curve y = x² at the point (1, 1) is:
If y = sin(2x), then dy/dx at x = π/6 equals:
The angle between the curves y = x² and y = 4 - x² at their point of intersection is:
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