Stoichiometry — Revision Notes
JEE Advanced · Chemistry
Quick revision notes for Stoichiometry — key concepts, formulas, and definitions for JEE Advanced Chemistry preparation.
Revision Notes — Stoichiometry
Key concepts, formulas, and definitions from Stoichiometry for JEE Advanced Chemistry preparation.
Key Topics to Revise
Basic Concepts and Formulas
- Gram equivalent (Eq) = w/Ew, where w = weight and Ew = equivalent weight
- Milliequivalent (mEq) = w/Ew × 1000
- Equivalents = N × V(L) and mEq = N × V(mL)
n-Factors of Important Compounds
- KMnO₄: n=5 (acidic), n=1 (strongly basic), n=3 (neutral/mild basic)
- K₂Cr₂O₇: n=6 (always acts as oxidizing agent)
- H₂O₂: n=2 (both as oxidizing and reducing agent)
Disproportionation Reactions
- Single substance acts as both oxidizing and reducing agent
- Different n-factors for oxidation and reduction half-reactions
- Effective n-factor = (n₁ × n₂)/(n₁ + n₂) where n₁, n₂ are individual n-factors
Hydrogen Peroxide - Volume Strength
- Volume strength = Volume of O₂ produced at STP by 1mL H₂O₂
- 1N H₂O₂ = 5.6 volume = 1.7% = 17g/L
- Commercial H₂O₂: 3% = 10 volume, 30% = 100 volume
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Key Concepts
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What topics are covered in Stoichiometry for JEE Advanced?
Stoichiometry is an important chapter in JEE Advanced Chemistry. It covers key concepts and formulas that are frequently tested in the exam. Key topics include: Basic Concepts and Formulas, n-Factors of Important Compounds, Disproportionation Reactions, Hydrogen Peroxide - Volume Strength.
How important is Stoichiometry for JEE Advanced?
Stoichiometry is a frequently tested chapter in JEE Advanced Chemistry. Questions from this chapter appear regularly in previous year papers. There are 51 practice questions available for this chapter.
How to prepare Stoichiometry for JEE Advanced?
Start by understanding the core concepts, then solve practice questions. Focus on formulas and their applications. Use revision notes for quick review before the exam.