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Chapter 8 of 9
Flashcards

Function

Gujarat Board · Class 11 · Statistics

Flashcards for Function — Gujarat Board Class 11 Statistics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts
20 Flashcards
Card 1Function Definition and Notation

Given f: {1, 2, 3, 4} → {5, 6, 7, 8} where f(x) = x + 4. Find f(2) and verify this is a function.

Answer

Step 1: Apply f(x) = x + 4 with x = 2 f(2) = 2 + 4 = 6 Step 2: Verify it's a function - f(1) = 5, f(2) = 6, f(3) = 7, f(4) = 8 - Each element in domain has exactly one image - All elements in domain

Card 2Domain and Range

For f(x) = 2x² + 1 with domain {-2, -1, 0, 1, 2}, find the range of f.

Answer

Step 1: Calculate f(x) for each domain element f(-2) = 2(-2)² + 1 = 2(4) + 1 = 9 f(-1) = 2(-1)² + 1 = 2(1) + 1 = 3 f(0) = 2(0)² + 1 = 0 + 1 = 1 f(1) = 2(1)² + 1 = 2(1) + 1 = 3 f(2) = 2(2)² + 1 = 2(4)

Card 3Types of Functions

Determine if f: {-2, -1, 1, 2} → {2, 5} where f(x) = x² + 1 is one-one or many-one.

Answer

Step 1: Calculate function values f(-2) = (-2)² + 1 = 4 + 1 = 5 f(-1) = (-1)² + 1 = 1 + 1 = 2 f(1) = (1)² + 1 = 1 + 1 = 2 f(2) = (2)² + 1 = 4 + 1 = 5 Step 2: Check for repeated images f(-1) = f(1) =

Card 4Types of Functions

For g: {1, 2, 3} → {5} where g(x) = 5, identify the type of function and find its range.

Answer

Step 1: Calculate function values g(1) = 5 g(2) = 5 g(3) = 5 Step 2: Analyze the pattern All domain elements map to the same value (5) Step 3: Classification This is a constant function because ever

Card 5Real Functions

Solve: If f(x) = (2x - 4)/(x + 7), find the value of x for which f(x) = 0.

Answer

Step 1: Set up the equation f(x) = 0 (2x - 4)/(x + 7) = 0 Step 2: For a fraction to equal zero, numerator must be zero 2x - 4 = 0 2x = 4 x = 2 Step 3: Verify denominator is not zero When x = 2: x +

Card 6Equal Functions

Given f(x) = x² - 2x + 1 and g(x) = (x - 1)², check if f = g for domain {0, 1, 2, 3}.

Answer

Step 1: Calculate f(x) for each domain value f(0) = 0² - 2(0) + 1 = 1 f(1) = 1² - 2(1) + 1 = 0 f(2) = 2² - 2(2) + 1 = 1 f(3) = 3² - 2(3) + 1 = 4 Step 2: Calculate g(x) for each domain value g(0) = (0

Card 7Real Functions

If f(x) = 1/(1 - x²) where x ∈ R - {-1, 1}, calculate f(2) - f(-2).

Answer

Step 1: Calculate f(2) f(2) = 1/(1 - 2²) = 1/(1 - 4) = 1/(-3) = -1/3 Step 2: Calculate f(-2) f(-2) = 1/(1 - (-2)²) = 1/(1 - 4) = 1/(-3) = -1/3 Step 3: Find f(2) - f(-2) f(2) - f(-2) = -1/3 - (-1/3)

Card 8Domain and Range

For h: A → B where A = {2, 5, 6}, B = {1, 2/3, 4/5, 11/7, 13/8} and h(x) = (2x-1)/(x+1), find the range.

Answer

Step 1: Calculate h(x) for each domain element h(2) = (2(2)-1)/(2+1) = (4-1)/(3) = 3/3 = 1 h(5) = (2(5)-1)/(5+1) = (10-1)/(6) = 9/6 = 3/2 h(6) = (2(6)-1)/(6+1) = (12-1)/(7) = 11/7 Step 2: Check which

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Frequently Asked Questions

What are the important topics in Function for Gujarat Board Class 11 Statistics?

Function covers several key topics that are frequently asked in Gujarat Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 20 flashcards for Function covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

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