Permutations, Combination and Binomial Expansion
Gujarat Board · Class 11 · Statistics
Flashcards for Permutations, Combination and Binomial Expansion — Gujarat Board Class 11 Statistics. Quick Q&A cards covering key concepts, definitions, and formulas.
What is the Fundamental Principle of Counting for Addition?
Answer
If there are m distinct things in Group 1 and n distinct things in Group 2, then selection of one thing from the combined groups can be done in m + n ways. The keyword 'OR' indicates addition. Example
What is the Fundamental Principle of Counting for Multiplication?
Answer
If the first operation can be done in m ways and the second operation can be done in n ways, then both operations together can be done in m × n ways. The keyword 'AND' indicates multiplication. Exampl
What is n! (n factorial) and how is it calculated?
Answer
n! = n × (n-1) × (n-2) × ... × 3 × 2 × 1 It is the product of all natural numbers from 1 to n. Examples: 5! = 5 × 4 × 3 × 2 × 1 = 120 3! = 3 × 2 × 1 = 6 1! = 1 0! = 1 (by definition)
Define Permutation and state its formula.
Answer
Permutation is the arrangement of r distinct things out of n distinct things where ORDER MATTERS. Formula: ⁿPᵣ = n!/(n-r)! where n ≥ r ≥ 0 Example: Arranging 3 students out of 5 students in 3 chairs =
What are the important special cases of Permutation?
Answer
ⁿP₀ = 1 (no arrangements) ⁿPₙ = n! (all things arranged) ⁿP₁ = n (one thing from n) ⁿPₙ₋₁ = n! (leave one thing out) Examples: ⁵P₀ = 1, ⁵P₅ = 5! = 120, ⁵P₁ = 5, ⁵P₄ = 5! = 120
Define Combination and state its formula.
Answer
Combination is the selection of r things out of n distinct things where ORDER DOES NOT MATTER. Formula: ⁿCᵣ = n!/[r!(n-r)!] where n ≥ r ≥ 0 Example: Selecting 3 friends out of 5 friends = ⁵C₃ = 5!/(3!
What is the relationship between Permutation and Combination?
Answer
ⁿPᵣ = ⁿCᵣ × r! OR ⁿCᵣ = ⁿPᵣ/r! This means: For each combination of r things, there are r! different arrangements (permutations). Example: ⁵C₃ = 10 combinations, but ⁵P₃ = 10 × 3! = 60 permutations
What are the important special cases of Combination?
Answer
ⁿC₀ = 1 (select nothing) ⁿCₙ = 1 (select everything) ⁿC₁ = n (select one thing) ⁿCₙ₋₁ = n (leave one thing) ⁿCᵣ = ⁿCₙ₋ᵣ (symmetry property) Example: ⁵C₂ = ⁵C₃ = 10
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Permutations, Combination and Binomial Expansion covers several key topics that are frequently asked in Gujarat Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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