Polynomials
Karnataka Board · Class 10 · Mathematics
Flashcards for Polynomials — Karnataka Board Class 10 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Find the zeros of the polynomial p(x) = x² - 5x + 6
Answer
Step 1: Factor the polynomial. Look for two numbers that multiply to 6 and add to -5. Those are -2 and -3. Step 2: x² - 5x + 6 = (x - 2)(x - 3) Step 3: Set each factor to zero: x - 2 = 0 or x - 3 = 0
Verify the relationship between zeros and coefficients for p(x) = 2x² - 7x + 3
Answer
Step 1: Find zeros by factoring: 2x² - 7x + 3 = (2x - 1)(x - 3) Zeros: x = 1/2 and x = 3 Step 2: Check sum of zeros: Sum = 1/2 + 3 = 7/2 From formula: -b/a = -(-7)/2 = 7/2 ✓ Step 3: Check product of
If α and β are zeros of x² - 6x + 8, find α + β and αβ without finding the actual zeros
Answer
Given: p(x) = x² - 6x + 8 Compare with ax² + bx + c where a = 1, b = -6, c = 8 Step 1: Sum of zeros formula: α + β = -b/a = -(-6)/1 = 6 Step 2: Product of zeros formula: αβ = c/a = 8/1 = 8 Answer:
Find a quadratic polynomial whose zeros are 3 and -2
Answer
Step 1: If zeros are α = 3 and β = -2, then: Sum of zeros = α + β = 3 + (-2) = 1 Product of zeros = αβ = 3 × (-2) = -6 Step 2: Use the relationship: α + β = -b/a and αβ = c/a Step 3: Taking a = 1: -
Solve: 3x² - 12x = 0
Answer
Step 1: Factor out common terms: 3x² - 12x = 3x(x - 4) = 0 Step 2: Apply zero product property: Either 3x = 0 or (x - 4) = 0 Step 3: Solve each equation: From 3x = 0: x = 0 From x - 4 = 0: x = 4 St
Find the value of k if x² + kx + 12 has equal zeros
Answer
For equal zeros, the discriminant must be zero. For ax² + bx + c, discriminant = b² - 4ac Step 1: Identify coefficients: a = 1, b = k, c = 12 Step 2: Set discriminant = 0: k² - 4(1)(12) = 0 k² - 48
What is the degree and leading coefficient of 5x³ - 2x² + 7x - 1?
Answer
Step 1: Identify the highest power term: The term with highest power is 5x³ Step 2: Find degree: Degree = highest power of x = 3 Step 3: Find leading coefficient: Leading coefficient = coefficient o
If p(x) = x² - 4x + 3, find p(2) and p(0)
Answer
Given: p(x) = x² - 4x + 3 Step 1: Find p(2): Substitute x = 2: p(2) = (2)² - 4(2) + 3 p(2) = 4 - 8 + 3 = -1 Step 2: Find p(0): Substitute x = 0: p(0) = (0)² - 4(0) + 3 p(0) = 0 - 0 + 3 = 3 Answer:
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What are the important topics in Polynomials for Karnataka Board Class 10 Mathematics?
Polynomials covers several key topics that are frequently asked in Karnataka Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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There are 20 flashcards for Polynomials covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.
Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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