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Chapter 9 of 13
Flashcards

Electricity

Karnataka Board · Class 10 · Science

Flashcards for Electricity — Karnataka Board Class 10 Science. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts
20 Flashcards
Card 1Ohm's Law and Power

An electric heater draws 5 A current from a 220 V supply. Calculate its resistance and the power consumed.

Answer

Using Ohm's law: R = V/I = 220V/5A = 44Ω Power consumed: P = VI = 220V × 5A = 1100W = 1.1kW This heater consumes 1.1 units of electricity per hour.

Card 2Heating Effect of Current

Why does the filament of an electric bulb glow but the connecting wires remain cool?

Answer

The filament has much higher resistance than connecting wires. When current flows, heat generated (H = I²Rt) is proportional to resistance. The high-resistance filament gets hot enough to glow (around

Card 3Electric Current

What is electric current and how is it measured?

Answer

Electric current is the rate of flow of electric charge through a conductor. Formula: I = Q/t, where Q is charge in coulombs and t is time in seconds. Unit: Ampere (A). Measured using an ammeter conne

Card 4Resistor Combinations

Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. Find the equivalent resistance.

Answer

For parallel connection: 1/Rp = 1/R₁ + 1/R₂ + 1/R₃ 1/Rp = 1/2 + 1/3 + 1/6 = 3/6 + 2/6 + 1/6 = 6/6 = 1 Therefore, Rp = 1Ω Note: Parallel resistance is always less than the smallest individual resistanc

Card 5Parallel Circuits

Why are household appliances connected in parallel instead of series?

Answer

In parallel connection: 1) Each appliance gets full voltage (220V), 2) Each works independently - if one fails, others continue working, 3) Different appliances can draw different currents as needed,

Card 6Factors Affecting Resistance

A wire has resistance 10Ω. If it's stretched to double its length, what happens to its resistance?

Answer

When length doubles, cross-sectional area halves (volume remains constant). R = ρl/A. New resistance = ρ(2l)/(A/2) = 4ρl/A = 4R New resistance = 4 × 10Ω = 40Ω Resistance becomes 4 times the original v

Card 7Current Measurement

What happens during the process of measuring current in a circuit?

Answer

Steps: 1) Break the circuit at the point where current is to be measured, 2) Connect ammeter in series so all current flows through it, 3) Ensure correct polarity (+ terminal to higher potential), 4)

Card 8Electric Power and Energy

An electric iron rated 1000W is used for 2 hours daily for 30 days. Calculate the electricity bill if the rate is ₹5 per unit.

Answer

Energy consumed = Power × Time = 1000W × 2h × 30 days = 60,000Wh = 60kWh = 60 units Cost = 60 units × ₹5/unit = ₹300 This shows how power rating and usage time affect electricity bills.

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Frequently Asked Questions

What are the important topics in Electricity for Karnataka Board Class 10 Science?

Electricity covers several key topics that are frequently asked in Karnataka Board Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 20 flashcards for Electricity covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.