Three Dimensional Geometry
Karnataka Board · Class 12 · Mathematics
Flashcards for Three Dimensional Geometry — Karnataka Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
What are direction cosines of a line? How are they denoted?
Answer
Direction cosines are the cosines of the angles made by a line with the positive directions of the x, y, and z axes. If a line makes angles α, β, and γ with the x, y, and z axes respectively, then cos
What is the fundamental property of direction cosines?
Answer
For any line in space, if l, m, n are the direction cosines, then: l² + m² + n² = 1. This is because the sum of squares of direction cosines of any line is always equal to 1.
Find the direction cosines of a line passing through points P(1, 2, 3) and Q(4, 6, 8).
Answer
Given P(1, 2, 3) and Q(4, 6, 8) Direction ratios = (4-1, 6-2, 8-3) = (3, 4, 5) PQ = √(3² + 4² + 5²) = √(9 + 16 + 25) = √50 = 5√2 Direction cosines = (3/5√2, 4/5√2, 5/5√2) = (3/5√2, 4/5√2, 1/√2)
What are direction ratios? How are they related to direction cosines?
Answer
Direction ratios are any three numbers which are proportional to the direction cosines of a line. If l, m, n are direction cosines and a, b, c are direction ratios, then a = λl, b = λm, c = λn for som
How do you find direction cosines from direction ratios a, b, c?
Answer
If a, b, c are direction ratios, then direction cosines are: l = ±a/√(a² + b² + c²) m = ±b/√(a² + b² + c²) n = ±c/√(a² + b² + c²) The sign depends on the orientation of the line.
Write the vector equation of a line passing through point A with position vector 'a' and parallel to vector 'b'.
Answer
The vector equation of the line is: r⃗ = a⃗ + λb⃗ where r⃗ is the position vector of any point on the line, a⃗ is the position vector of the given point A, b⃗ is the parallel vector, and λ is a parame
What is the Cartesian equation of a line passing through point (x₁, y₁, z₁) with direction ratios a, b, c?
Answer
The Cartesian equation is: (x - x₁)/a = (y - y₁)/b = (z - z₁)/c This is also called the symmetric form of the equation of a line.
Find the equation of a line passing through (2, -1, 3) and parallel to vector 3î + 4ĵ - 5k̂.
Answer
Given point: (2, -1, 3), Direction vector: 3î + 4ĵ - 5k̂ Direction ratios: 3, 4, -5 Cartesian equation: (x - 2)/3 = (y + 1)/4 = (z - 3)/(-5) Vector equation: r⃗ = (2î - ĵ + 3k̂) + λ(3î + 4ĵ - 5k̂)
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Three Dimensional Geometry covers several key topics that are frequently asked in Karnataka Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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