Number Systems
Karnataka Board · Class 9 · Mathematics
Flashcards for Number Systems — Karnataka Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Express 7/8 as a decimal. What type of decimal expansion is it?
Answer
Step 1: Divide 7 by 8 using long division: 0.875 8)7.000 64 --- 60 56 --- 40 40 --- 0 Step 2: Since remainder becomes 0, it's a terminating decimal. Answer: 7/8 = 0.875 (terminating
Convert 0.333... (0.3̄) to the form p/q where p and q are integers.
Answer
Step 1: Let x = 0.333... Step 2: Multiply by 10: 10x = 3.333... Step 3: Subtract original equation: 10x - x = 3.333... - 0.333... Step 4: Simplify: 9x = 3 Step 5: Solve for x: x = 3/9 = 1/3 Answer: 0
Is √25 rational or irrational? Justify your answer.
Answer
Step 1: Find the value of √25 √25 = 5 (since 5² = 25) Step 2: Check if 5 can be written as p/q 5 = 5/1, where p = 5, q = 1 (both integers, q ≠ 0) Step 3: Conclusion Since √25 = 5 can be expressed as
Find five rational numbers between 1/3 and 1/2.
Answer
Method: Convert to common denominator Step 1: LCM of 3 and 2 is 6 1/3 = 2/6 and 1/2 = 3/6 Step 2: Since we need 5 numbers, multiply by 10 1/3 = 20/60 and 1/2 = 30/60 Step 3: Find rational numbers be
Show that 2 + √3 is an irrational number.
Answer
Proof by contradiction: Step 1: Assume 2 + √3 is rational Then 2 + √3 = p/q where p, q are integers, q ≠ 0 Step 2: Rearrange √3 = p/q - 2 = (p - 2q)/q Step 3: Analyze Since p, q are integers, (p - 2
Simplify: (√5 + √2)(√5 - √2)
Answer
Step 1: Apply the identity (a + b)(a - b) = a² - b² Here, a = √5 and b = √2 Step 2: Substitute (√5 + √2)(√5 - √2) = (√5)² - (√2)² Step 3: Calculate = 5 - 2 = 3 Answer: 3
Rationalise the denominator: 1/(3 + √2)
Answer
Step 1: Multiply numerator and denominator by conjugate (3 - √2) 1/(3 + √2) × (3 - √2)/(3 - √2) Step 2: Apply (a + b)(a - b) = a² - b² in denominator Numerator: 1 × (3 - √2) = 3 - √2 Denominator: (3
Express 2.3̄7̄ (where 37 repeats) in the form p/q.
Answer
Step 1: Let x = 2.373737... Step 2: Since 2 digits repeat, multiply by 100 100x = 237.373737... Step 3: Subtract to eliminate repeating part 100x - x = 237.373737... - 2.373737... 99x = 235 Step 4:
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What are the important topics in Number Systems for Karnataka Board Class 9 Mathematics?
Number Systems covers several key topics that are frequently asked in Karnataka Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Number Systems — Karnataka Board Class 9 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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There are 20 flashcards for Number Systems covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.
Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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