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Flashcards

Polynomials

Karnataka Board · Class 9 · Mathematics

Flashcards for Polynomials — Karnataka Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts
20 Flashcards
Card 1Polynomial Classification

Find the degree and identify the type of polynomial: 5x³ - 2x² + 7x - 3

Answer

Step 1: Identify the highest power of x → x³ has power 3. Step 2: Degree = 3. Step 3: Since degree = 3, it's a cubic polynomial. Step 4: Count terms → 4 terms, so it's not a monomial, binomial, or tri

Card 2Polynomial Evaluation

If p(x) = 3x² - 5x + 2, find p(2) and p(-1)

Answer

For p(2): Step 1: Substitute x = 2 → p(2) = 3(2)² - 5(2) + 2. Step 2: Calculate → p(2) = 3(4) - 10 + 2 = 12 - 10 + 2 = 4. For p(-1): Step 1: Substitute x = -1 → p(-1) = 3(-1)² - 5(-1) + 2. Step 2: Cal

Card 3Zeros of Polynomials

Check if x = 3 is a zero of the polynomial p(x) = x² - 5x + 6

Answer

Step 1: Substitute x = 3 in p(x). Step 2: p(3) = (3)² - 5(3) + 6. Step 3: Calculate → p(3) = 9 - 15 + 6 = 0. Step 4: Since p(3) = 0, x = 3 is a zero of the polynomial. Answer: Yes, x = 3 is a zero bec

Card 4Zeros of Polynomials

Find the zero of the linear polynomial p(x) = 4x - 12

Answer

Step 1: Set polynomial equal to zero → 4x - 12 = 0. Step 2: Add 12 to both sides → 4x = 12. Step 3: Divide both sides by 4 → x = 3. Step 4: Verify by substituting → p(3) = 4(3) - 12 = 0 ✓. Answer: x =

Card 5Factor Theorem

Use the Factor Theorem to check if (x - 2) is a factor of x³ - 3x² + 4x - 2

Answer

Step 1: For (x - 2) to be a factor, p(2) must equal 0. Step 2: Let p(x) = x³ - 3x² + 4x - 2. Step 3: Find p(2) → p(2) = (2)³ - 3(2)² + 4(2) - 2. Step 4: Calculate → p(2) = 8 - 12 + 8 - 2 = 2. Step 5:

Card 6Factor Theorem

If (x + 1) is a factor of x³ + ax² + 2x + a, find the value of a

Answer

Step 1: Since (x + 1) is a factor, p(-1) = 0 by Factor Theorem. Step 2: Let p(x) = x³ + ax² + 2x + a. Step 3: Find p(-1) → p(-1) = (-1)³ + a(-1)² + 2(-1) + a. Step 4: Simplify → p(-1) = -1 + a - 2 + a

Card 7Factorization

Factorize x² - 7x + 12 by splitting the middle term

Answer

Step 1: Find two numbers that multiply to 12 and add to -7. Step 2: Factors of 12: 1×12, 2×6, 3×4. Check: -3 + (-4) = -7 and (-3)×(-4) = 12 ✓. Step 3: Split middle term → x² - 3x - 4x + 12. Step 4: Gr

Card 8Factorization

Factorize 6x² + 11x + 3 using splitting method

Answer

Step 1: Find two numbers that multiply to (6×3) = 18 and add to 11. Step 2: Factors of 18: Check 9 + 2 = 11 and 9×2 = 18 ✓. Step 3: Split middle term → 6x² + 9x + 2x + 3. Step 4: Group → 3x(2x + 3) +

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Frequently Asked Questions

What are the important topics in Polynomials for Karnataka Board Class 9 Mathematics?

Polynomials covers several key topics that are frequently asked in Karnataka Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 20 flashcards for Polynomials covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

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