Polynomials
Karnataka Board · Class 9 · Mathematics
Flashcards for Polynomials — Karnataka Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Find the degree and identify the type of polynomial: 5x³ - 2x² + 7x - 3
Answer
Step 1: Identify the highest power of x → x³ has power 3. Step 2: Degree = 3. Step 3: Since degree = 3, it's a cubic polynomial. Step 4: Count terms → 4 terms, so it's not a monomial, binomial, or tri
If p(x) = 3x² - 5x + 2, find p(2) and p(-1)
Answer
For p(2): Step 1: Substitute x = 2 → p(2) = 3(2)² - 5(2) + 2. Step 2: Calculate → p(2) = 3(4) - 10 + 2 = 12 - 10 + 2 = 4. For p(-1): Step 1: Substitute x = -1 → p(-1) = 3(-1)² - 5(-1) + 2. Step 2: Cal
Check if x = 3 is a zero of the polynomial p(x) = x² - 5x + 6
Answer
Step 1: Substitute x = 3 in p(x). Step 2: p(3) = (3)² - 5(3) + 6. Step 3: Calculate → p(3) = 9 - 15 + 6 = 0. Step 4: Since p(3) = 0, x = 3 is a zero of the polynomial. Answer: Yes, x = 3 is a zero bec
Find the zero of the linear polynomial p(x) = 4x - 12
Answer
Step 1: Set polynomial equal to zero → 4x - 12 = 0. Step 2: Add 12 to both sides → 4x = 12. Step 3: Divide both sides by 4 → x = 3. Step 4: Verify by substituting → p(3) = 4(3) - 12 = 0 ✓. Answer: x =
Use the Factor Theorem to check if (x - 2) is a factor of x³ - 3x² + 4x - 2
Answer
Step 1: For (x - 2) to be a factor, p(2) must equal 0. Step 2: Let p(x) = x³ - 3x² + 4x - 2. Step 3: Find p(2) → p(2) = (2)³ - 3(2)² + 4(2) - 2. Step 4: Calculate → p(2) = 8 - 12 + 8 - 2 = 2. Step 5:
If (x + 1) is a factor of x³ + ax² + 2x + a, find the value of a
Answer
Step 1: Since (x + 1) is a factor, p(-1) = 0 by Factor Theorem. Step 2: Let p(x) = x³ + ax² + 2x + a. Step 3: Find p(-1) → p(-1) = (-1)³ + a(-1)² + 2(-1) + a. Step 4: Simplify → p(-1) = -1 + a - 2 + a
Factorize x² - 7x + 12 by splitting the middle term
Answer
Step 1: Find two numbers that multiply to 12 and add to -7. Step 2: Factors of 12: 1×12, 2×6, 3×4. Check: -3 + (-4) = -7 and (-3)×(-4) = 12 ✓. Step 3: Split middle term → x² - 3x - 4x + 12. Step 4: Gr
Factorize 6x² + 11x + 3 using splitting method
Answer
Step 1: Find two numbers that multiply to (6×3) = 18 and add to 11. Step 2: Factors of 18: Check 9 + 2 = 11 and 9×2 = 18 ✓. Step 3: Split middle term → 6x² + 9x + 2x + 3. Step 4: Group → 3x(2x + 3) +
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What are the important topics in Polynomials for Karnataka Board Class 9 Mathematics?
Polynomials covers several key topics that are frequently asked in Karnataka Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Polynomials — Karnataka Board Class 9 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
How many flashcards are available for Polynomials?
There are 20 flashcards for Polynomials covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.
Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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