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Flashcards

Ionic Equilibrium

Kerala Board · Class 12 · Chemistry

Flashcards for Ionic Equilibrium — Kerala Board Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

85 questions20 flashcards5 concepts
20 Flashcards
Card 1Acid-Base Concepts

Define an Arrhenius acid and give an example with its ionization equation.

Answer

An Arrhenius acid is a substance that produces H⁺ ions when dissolved in water. Example: HCl (hydrochloric acid) HCl(aq) → H⁺(aq) + Cl⁻(aq) The H⁺ ion actually binds with water to form hydronium ion

Card 2Acid-Base Concepts

What is a conjugate acid-base pair? Identify the conjugate pairs in: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻

Answer

A conjugate acid-base pair consists of two species that differ by the gain or loss of one proton (H⁺). In the reaction: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻ Conjugate pairs: 1. NH₃/NH₄⁺ (NH₃ is base, NH₄⁺ is its

Card 3Ionization Constants

Write the expression for acid dissociation constant (Ka) for a weak acid HA.

Answer

For the equilibrium: HA(aq) + H₂O(l) ⇌ H₃O⁺(aq) + A⁻(aq) Kₐ = [H₃O⁺][A⁻]/[HA] Where: • [HA] = concentration of undissociated acid • [H₃O⁺] = concentration of hydronium ions • [A⁻] = concentration of

Card 4Ionization Constants

Derive the relationship between degree of dissociation (α) and Ka for a weak acid.

Answer

For weak acid HA with initial concentration c and degree of dissociation α: At equilibrium: [HA] = c(1-α) [H₃O⁺] = [A⁻] = cα Kₐ = [H₃O⁺][A⁻]/[HA] = (cα)(cα)/c(1-α) = c²α²/c(1-α) = cα²/(1-α) For ver

Card 5Water Ionization

What is the ionic product of water (Kw)? Write its expression and value at 25°C.

Answer

Kw is the ionic product constant of water representing auto-ionization: H₂O + H₂O ⇌ H₃O⁺ + OH⁻ Kw = [H₃O⁺][OH⁻] = 1.0 × 10⁻¹⁴ mol²dm⁻⁶ at 25°C In pure water: [H₃O⁺] = [OH⁻] = 1.0 × 10⁻⁷ mol dm⁻³ T

Card 6pH and pOH

Define pH and calculate the pH of 0.01 M HCl solution.

Answer

pH = -log₁₀[H₃O⁺] For 0.01 M HCl: HCl is a strong acid, so it ionizes completely: HCl(aq) → H⁺(aq) + Cl⁻(aq) [H₃O⁺] = 0.01 M = 1.0 × 10⁻² M pH = -log₁₀(1.0 × 10⁻²) = -(-2.0) = 2.0 The solution is

Card 7pH and pOH

State the relationship between pH, pOH, and pKw. How do you classify solutions based on pH?

Answer

pH + pOH = pKw = 14 (at 25°C) Solution classification: • Neutral solution: pH = 7, [H₃O⁺] = [OH⁻] • Acidic solution: pH < 7, [H₃O⁺] > [OH⁻] • Basic solution: pH > 7, [H₃O⁺] < [OH⁻] If pH is known: p

Card 8Common Ion Effect

What is the common ion effect? Explain with the example of CH₃COOH and CH₃COONa mixture.

Answer

Common ion effect: The suppression of ionization of a weak electrolyte by the addition of a salt containing a common ion. Example: CH₃COOH + CH₃COONa mixture CH₃COOH(aq) ⇌ H⁺(aq) + CH₃COO⁻(aq) CH₃CO

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