Circles
Kerala Board · Class 12 · Mathematics
Flashcards for Circles — Kerala Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
What is the definition of a circle and what is its standard form equation?
Answer
A circle is the locus of a point which moves in a plane such that its distance from a fixed point remains constant. The fixed point is called the center and the constant distance is the radius. Stand
Convert the general form x² + y² + 2gx + 2fy + c = 0 to standard form and find center and radius.
Answer
General Form: x² + y² + 2gx + 2fy + c = 0 Step 1: Complete the square (x² + 2gx + g²) + (y² + 2fy + f²) = g² + f² - c Step 2: Standard form (x + g)² + (y + f)² = g² + f² - c Center: (-g, -f) Radius
Find the equation of circle with center (2, -3) and radius 4.
Answer
Given: Center (h, k) = (2, -3), Radius r = 4 Step 1: Use standard form (x - h)² + (y - k)² = r² Step 2: Substitute values (x - 2)² + (y - (-3))² = 4² (x - 2)² + (y + 3)² = 16 Step 3: Expand to gene
Find the center and radius of the circle x² + y² - 6x + 8y - 11 = 0
Answer
Given: x² + y² - 6x + 8y - 11 = 0 Step 1: Compare with x² + y² + 2gx + 2fy + c = 0 2g = -6 → g = -3 2f = 8 → f = 4 c = -11 Step 2: Find center and radius Center = (-g, -f) = (3, -4) Radius = √(g² +
What is the equation of a circle when endpoints of a diameter are given as (x₁, y₁) and (x₂, y₂)?
Answer
Diameter Form of Circle: (x - x₁)(x - x₂) + (y - y₁)(y - y₂) = 0 Reason: If P(x, y) is any point on the circle, then angle APB = 90° (angle in semicircle) This means AP ⊥ BP, so slope of AP × slope o
What are the parametric equations of a circle and when are they used?
Answer
Parametric Form of Circle: For circle with center (h, k) and radius r: x = h + r cos θ y = k + r sin θ where θ is the parameter (0 ≤ θ < 2π) For circle with center at origin: x = r cos θ, y = r sin θ
How do you find the equation of a circle passing through three non-collinear points?
Answer
Method: Use general form x² + y² + 2gx + 2fy + c = 0 Step 1: Substitute each point to get 3 equations Step 2: Solve for g, f, and c Example: Points (1, 1), (2, -1), (3, 2) Substituting: 1 + 1 + 2g
How do you determine the position of a point P(x₁, y₁) with respect to circle S = x² + y² + 2gx + 2fy + c = 0?
Answer
Use S₁₁ = x₁² + y₁² + 2gx₁ + 2fy₁ + c Position of point P: • S₁₁ < 0: P is INSIDE the circle • S₁₁ = 0: P is ON the circle • S₁₁ > 0: P is OUTSIDE the circle Example: Point (2, 1) and circle x² + y²
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What are the important topics in Circles for Kerala Board Class 12 Mathematics?
Circles covers several key topics that are frequently asked in Kerala Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Circles — Kerala Board Class 12 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
How many flashcards are available for Circles?
There are 20 flashcards for Circles covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.
Sources & Official References
- Kerala Board of Public Examinations — keralapareekshabhavan.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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