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Chapter 10 of 29
Flashcards

Current Electricity

Kerala Board · Class 12 · Physics

Flashcards for Current Electricity — Kerala Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions25 flashcards5 concepts
25 Flashcards
Card 1Electric Current

Define electric current and state its SI unit. How is it related to charge flow?

Answer

Electric current is the rate of flow of electric charge through a conductor. I = q/t (for steady current) or I = dq/dt (for varying current). SI unit is Ampere (A). 1 ampere = 1 coulomb/1 second. Curr

Card 2Ohm's Law

State Ohm's Law and distinguish between ohmic and non-ohmic conductors with examples.

Answer

Ohm's Law: The electric current through a conductor is directly proportional to the potential difference across it (at constant temperature and pressure). V = IR. Ohmic conductors: Metals (copper, iro

Card 3Resistance and Resistivity

Derive the relationship between resistance and resistivity. What are their units?

Answer

R = ρl/A, where R = resistance, ρ = resistivity, l = length, A = cross-sectional area. Unit of resistance: Ohm (Ω). Unit of resistivity: Ohm-meter (Ωm). Resistivity depends only on material nature, wh

Card 4Electric Current

Calculate: If 6.0 × 10¹⁶ electrons pass through a wire's cross-section per second, find the current.

Answer

Given: n = 6.0 × 10¹⁶ electrons/s, e = 1.6 × 10⁻¹⁹ C Solution: Total charge per second, Q = ne = 6.0 × 10¹⁶ × 1.6 × 10⁻¹⁹ = 9.6 × 10⁻³ C/s Current I = Q/t = 9.6 × 10⁻³ A = 9.6 mA

Card 5Series Combination

For resistors in series combination, derive the equivalent resistance formula.

Answer

In series: Same current I flows through all resistors. V₁ = IR₁, V₂ = IR₂, V₃ = IR₃... Total voltage: V = V₁ + V₂ + V₃ + ... = I(R₁ + R₂ + R₃ + ...) Equivalent resistance: Rs = R₁ + R₂ + R₃ + ... Volt

Card 6Parallel Combination

For resistors in parallel combination, derive the equivalent resistance formula.

Answer

In parallel: Same voltage V across all resistors. I₁ = V/R₁, I₂ = V/R₂, I₃ = V/R₃... Total current: I = I₁ + I₂ + I₃ + ... = V(1/R₁ + 1/R₂ + 1/R₃ + ...) 1/Rp = 1/R₁ + 1/R₂ + 1/R₃ + ... Current divisio

Card 7Kirchhoff's Laws

State Kirchhoff's First Law (Junction Rule) and Second Law (Loop Rule) with their basis.

Answer

First Law (Junction Rule): Algebraic sum of currents at any junction = 0. Based on conservation of charge. ΣI = 0 Second Law (Loop Rule): Algebraic sum of potential differences in any closed loop = 0.

Card 8Wheatstone Bridge

Explain the principle of Wheatstone Bridge and state the balance condition.

Answer

Wheatstone Bridge: Used to measure unknown resistance accurately. Four resistances P, Q, R, S connected in diamond shape with galvanometer between opposite corners. Balance condition: P/Q = R/S (or PS

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Current Electricity covers several key topics that are frequently asked in Kerala Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

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