Simple Harmonic Motion
Kerala Board · Class 12 · Physics
Flashcards for Simple Harmonic Motion — Kerala Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
Define periodic motion and give two examples.
Answer
Periodic motion is motion that repeats itself at equal intervals of time. The smallest interval of time after which the motion repeats is called the time period (T). Examples: 1. Motion of planets ar
What is the difference between periodic motion and oscillatory motion?
Answer
Periodic Motion: Any motion that repeats after equal intervals of time (includes rotational motion like planets around sun) Oscillatory Motion: To and fro motion about a mean position (like pendulum,
Define Simple Harmonic Motion (SHM) and state its mathematical condition.
Answer
Simple Harmonic Motion: A particle executes SHM if its acceleration is directly proportional to its displacement from mean position and is always directed towards the mean position. Mathematical Cond
Write the differential equation of SHM and its general solution.
Answer
Differential Equation of SHM: d²x/dt² + ω²x = 0 General Solutions: x(t) = A sin(ωt + φ) or x(t) = A cos(ωt + φ) Where: - A = amplitude - ω = angular frequency - φ = initial phase - t = time
Define the following terms in SHM: Amplitude, Time Period, Frequency, Angular Frequency
Answer
Amplitude (A): Maximum displacement from mean position (units: m) Time Period (T): Time taken to complete one oscillation (units: s) T = 2π/ω Frequency (f): Number of oscillations per second (units:
Derive the velocity and acceleration expressions for SHM.
Answer
Given: x(t) = A sin(ωt + φ) Velocity: v = dx/dt = d/dt[A sin(ωt + φ)] v = Aω cos(ωt + φ) Maximum velocity: vₘₐₓ = Aω (at mean position) Acceleration: a = dv/dt = d/dt[Aω cos(ωt + φ)] a = -Aω² sin(ω
How is SHM related to uniform circular motion?
Answer
SHM can be represented as the projection of uniform circular motion on a diameter. Consider a particle moving in a circle of radius A with angular velocity ω: - Position: y = A sin(ωt) - The projecti
Derive the time period of a horizontal spring-mass system.
Answer
For horizontal spring-mass system: Restoring force: F = -kx (Hooke's law) From Newton's second law: F = ma Therefore: ma = -kx a = -(k/m)x Comparing with a = -ω²x: ω² = k/m ω = √(k/m) Time period:
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Sources & Official References
- Kerala Board of Public Examinations — keralapareekshabhavan.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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