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Chapter 13 of 29
Flashcards

Simple Harmonic Motion

Kerala Board · Class 12 · Physics

Flashcards for Simple Harmonic Motion — Kerala Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions22 flashcards5 concepts
22 Flashcards
Card 1Periodic Motion

Define periodic motion and give two examples.

Answer

Periodic motion is motion that repeats itself at equal intervals of time. The smallest interval of time after which the motion repeats is called the time period (T). Examples: 1. Motion of planets ar

Card 2Types of Motion

What is the difference between periodic motion and oscillatory motion?

Answer

Periodic Motion: Any motion that repeats after equal intervals of time (includes rotational motion like planets around sun) Oscillatory Motion: To and fro motion about a mean position (like pendulum,

Card 3Simple Harmonic Motion

Define Simple Harmonic Motion (SHM) and state its mathematical condition.

Answer

Simple Harmonic Motion: A particle executes SHM if its acceleration is directly proportional to its displacement from mean position and is always directed towards the mean position. Mathematical Cond

Card 4Mathematical Analysis

Write the differential equation of SHM and its general solution.

Answer

Differential Equation of SHM: d²x/dt² + ω²x = 0 General Solutions: x(t) = A sin(ωt + φ) or x(t) = A cos(ωt + φ) Where: - A = amplitude - ω = angular frequency - φ = initial phase - t = time

Card 5SHM Parameters

Define the following terms in SHM: Amplitude, Time Period, Frequency, Angular Frequency

Answer

Amplitude (A): Maximum displacement from mean position (units: m) Time Period (T): Time taken to complete one oscillation (units: s) T = 2π/ω Frequency (f): Number of oscillations per second (units:

Card 6Kinematics of SHM

Derive the velocity and acceleration expressions for SHM.

Answer

Given: x(t) = A sin(ωt + φ) Velocity: v = dx/dt = d/dt[A sin(ωt + φ)] v = Aω cos(ωt + φ) Maximum velocity: vₘₐₓ = Aω (at mean position) Acceleration: a = dv/dt = d/dt[Aω cos(ωt + φ)] a = -Aω² sin(ω

Card 7Circle of Reference

How is SHM related to uniform circular motion?

Answer

SHM can be represented as the projection of uniform circular motion on a diameter. Consider a particle moving in a circle of radius A with angular velocity ω: - Position: y = A sin(ωt) - The projecti

Card 8Spring-Mass System

Derive the time period of a horizontal spring-mass system.

Answer

For horizontal spring-mass system: Restoring force: F = -kx (Hooke's law) From Newton's second law: F = ma Therefore: ma = -kx a = -(k/m)x Comparing with a = -ω²x: ω² = k/m ω = √(k/m) Time period:

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Sources & Official References

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