Areas
Kerala Board · Class 9 · Mathematics
Flashcards for Areas — Kerala Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.
Find the area of a rectangle with length 12 cm and breadth 8 cm.
Answer
Formula: Area = length × breadth Step 1: Identify values → length = 12 cm, breadth = 8 cm Step 2: Apply formula → Area = 12 × 8 = 96 cm² Answer: 96 cm²
A parallelogram has base 15 cm and height 9 cm. Calculate its area.
Answer
Formula: Area of parallelogram = base × height Step 1: Identify values → base = 15 cm, height = 9 cm Step 2: Apply formula → Area = 15 × 9 = 135 cm² Note: Height is the perpendicular distance between
Find the area of a triangle with base 10 cm and height 6 cm.
Answer
Formula: Area of triangle = ½ × base × height Step 1: Identify values → base = 10 cm, height = 6 cm Step 2: Apply formula → Area = ½ × 10 × 6 = ½ × 60 = 30 cm² Answer: 30 cm²
A rhombus has diagonals of length 16 cm and 12 cm. Find its area.
Answer
Formula: Area of rhombus = ½ × d₁ × d₂ Step 1: Identify diagonal lengths → d₁ = 16 cm, d₂ = 12 cm Step 2: Apply formula → Area = ½ × 16 × 12 = ½ × 192 = 96 cm² Answer: 96 cm²
Calculate the area of a trapezium with parallel sides 14 cm and 10 cm, and height 8 cm.
Answer
Formula: Area of trapezium = ½ × (sum of parallel sides) × height Step 1: Identify values → parallel sides = 14 cm, 10 cm; height = 8 cm Step 2: Sum of parallel sides = 14 + 10 = 24 cm Step 3: Apply f
In triangle ABC, median AD divides the triangle. If area of triangle ABC is 60 cm², find the area of triangle ABD.
Answer
Property: A median divides a triangle into two triangles of equal areas Step 1: Identify total area → Area of △ABC = 60 cm² Step 2: Apply median property → △ABD and △ACD have equal areas Step 3: Calcu
Two parallelograms ABCD and PQRS lie on the same base and between the same parallels. If area of ABCD is 84 cm², find area of PQRS.
Answer
Property: Parallelograms on same base and between same parallels have equal areas Step 1: Identify given area → Area of ABCD = 84 cm² Step 2: Apply property → Since both parallelograms are on same bas
Find the area of a square field whose perimeter is 80 meters.
Answer
Step 1: Find side length from perimeter Perimeter of square = 4 × side 80 = 4 × side → side = 80 ÷ 4 = 20 m Step 2: Calculate area Area of square = side² = 20² = 400 m² Answer: 400 m²
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What are the important topics in Areas for Kerala Board Class 9 Mathematics?
Areas covers several key topics that are frequently asked in Kerala Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Areas — Kerala Board Class 9 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
How many flashcards are available for Areas?
There are 20 flashcards for Areas covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.
Sources & Official References
- Kerala Board of Public Examinations — keralapareekshabhavan.in
- National Education Policy 2020 — education.gov.in
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
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