Skip to main content
Chapter 2 of 15
Flashcards

Polynomials and Factorisation

Kerala Board · Class 9 · Mathematics

Flashcards for Polynomials and Factorisation — Kerala Board Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts
20 Flashcards
Card 1Polynomial Basics

Find the degree of the polynomial: 3x⁴ - 5x² + 7x - 2

Answer

Step 1: Identify the highest power of x in the polynomial. Step 2: Look at each term: 3x⁴ (degree 4), -5x² (degree 2), 7x (degree 1), -2 (degree 0) Step 3: The highest degree is 4. Answer: Degree = 4

Card 2Polynomial Evaluation

If p(x) = 2x³ - 3x + 1, find p(2)

Answer

Step 1: Substitute x = 2 in the polynomial p(x) = 2x³ - 3x + 1 Step 2: p(2) = 2(2)³ - 3(2) + 1 Step 3: p(2) = 2(8) - 6 + 1 Step 4: p(2) = 16 - 6 + 1 = 11 Answer: p(2) = 11

Card 3Zeros of Polynomials

Find the zero of the polynomial: 3x - 15

Answer

Step 1: Set the polynomial equal to zero: 3x - 15 = 0 Step 2: Add 15 to both sides: 3x = 15 Step 3: Divide both sides by 3: x = 5 Step 4: Verify: 3(5) - 15 = 15 - 15 = 0 ✓ Answer: x = 5

Card 4Remainder Theorem

Use the remainder theorem to find the remainder when x³ + 2x² - x + 3 is divided by (x - 1)

Answer

Step 1: By remainder theorem, remainder = p(a) where divisor is (x - a) Step 2: Here divisor is (x - 1), so a = 1 Step 3: p(x) = x³ + 2x² - x + 3 Step 4: p(1) = (1)³ + 2(1)² - (1) + 3 Step 5: p(1) = 1

Card 5Factor Theorem

Check if (x + 2) is a factor of x³ + 3x² + 3x + 2

Answer

Step 1: Use factor theorem - if (x + 2) is a factor, then p(-2) = 0 Step 2: p(x) = x³ + 3x² + 3x + 2 Step 3: p(-2) = (-2)³ + 3(-2)² + 3(-2) + 2 Step 4: p(-2) = -8 + 3(4) - 6 + 2 Step 5: p(-2) = -8 + 1

Card 6Factorisation

Factorise: x² + 7x + 12

Answer

Step 1: Find two numbers that multiply to 12 and add to 7 Step 2: Consider pairs: (1,12), (2,6), (3,4) Step 3: Check: 3 + 4 = 7 and 3 × 4 = 12 ✓ Step 4: x² + 7x + 12 = x² + 3x + 4x + 12 Step 5: = x(x

Card 7Algebraic Identities

Expand using identity: (2x + 3)²

Answer

Step 1: Use identity (a + b)² = a² + 2ab + b² Step 2: Here a = 2x, b = 3 Step 3: (2x + 3)² = (2x)² + 2(2x)(3) + (3)² Step 4: = 4x² + 12x + 9 Answer: 4x² + 12x + 9

Card 8Algebraic Identities

Factorise using identity: 9x² - 25

Answer

Step 1: Recognize as difference of squares: a² - b² Step 2: 9x² = (3x)² and 25 = (5)² Step 3: Use identity a² - b² = (a + b)(a - b) Step 4: 9x² - 25 = (3x)² - (5)² = (3x + 5)(3x - 5) Answer: (3x + 5)(

+12 more flashcards available

Practice All

Get detailed flashcards for Polynomials and Factorisation

Super Tutor gives you interactive content for every chapter of Kerala Board Class 9 Mathematics — summaries, quizzes, flashcards, and more.

Try Super Tutor — It's Free

Frequently Asked Questions

What are the important topics in Polynomials and Factorisation for Kerala Board Class 9 Mathematics?

Polynomials and Factorisation covers several key topics that are frequently asked in Kerala Board Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 20 flashcards for Polynomials and Factorisation covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.