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Redox Reactions

Maharashtra Board · Class 11 · Chemistry

Flashcards for Redox Reactions — Maharashtra Board Class 11 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

42 questions20 flashcards5 concepts

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20 Flashcards
Card 1Classical Redox Concepts

What is the classical definition of oxidation? Give two examples.

Answer

Classical oxidation is the combination of an element or substance with oxygen. Examples: 1. C(s) + O₂(g) → CO₂(g) (carbon oxidation) 2. 2Mg(s) + O₂(g) → 2MgO(s) (magnesium oxidation) This definition l

Card 2Classical Redox Concepts

Define oxidizing agent (oxidant) and reducing agent (reductant) with their characteristics.

Answer

Oxidizing Agent (Oxidant): A substance that causes oxidation of another species while itself undergoing reduction. It accepts electrons. Reducing Agent (Reductant): A substance that causes reduction

Card 3Modern Redox Theory

State the modern definition of oxidation and reduction in terms of electron transfer.

Answer

Modern Definitions: Oxidation: Loss of electrons by a species Example: Mg → Mg²⁺ + 2e⁻ Reduction: Gain of electrons by a species Example: Cu²⁺ + 2e⁻ → Cu Redox Reaction: Simultaneous occurrence of

Card 4Oxidation Numbers

What is oxidation number? Why is this concept important for understanding redox reactions?

Answer

Oxidation Number: The number of electrical charges an atom carries in a compound, assuming complete electron transfer in covalent bonds. Importance: 1. Helps identify redox reactions involving covale

Card 5Oxidation Numbers

List the first four rules for assigning oxidation numbers with examples.

Answer

Rule 1: Oxidation number of atoms in free state = 0 Example: H₂, O₂, Cl₂, Ca all have O.N. = 0 Rule 2: O.N. of atom in monoatomic ion = its charge Example: Na⁺ has O.N. = +1, Cl⁻ has O.N. = -1 Rule

Card 6Oxidation Numbers

State the remaining rules (5-8) for assigning oxidation numbers.

Answer

Rule 5: O.N. of fluorine = -1 always; other halogens usually -1 in halides Example: HF (F = -1), NaCl (Cl = -1) Rule 6: Sum of O.N. in neutral molecule = 0 Example: In CO₂: C + 2(O) = 0, so C = +4 R

Card 7Oxidation Numbers

Calculate the oxidation number of chromium in K₂Cr₂O₇.

Answer

Given: K₂Cr₂O₇ Step 1: Assign known oxidation numbers K = +1 (alkali metal) O = -2 (standard rule) Step 2: Apply rule for neutral molecule Sum of all O.N. = 0 2(K) + 2(Cr) + 7(O) = 0 2(+1) + 2(Cr) +

Card 8Oxidation Numbers

What is Stock notation? Give three examples with their Stock notation representation.

Answer

Stock Notation: A system of representing oxidation states using Roman numerals in parentheses after the chemical symbol, named after Alfred Stock. Examples: 1. AuCl → Au(I)Cl (gold with +1 oxidation

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