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Chapter 11 of 14
Flashcards

Electric Current Through Conductors

Maharashtra Board · Class 11 · Physics

Flashcards for Electric Current Through Conductors — Maharashtra Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts
24 Flashcards
Card 1Electric Current

What is electric current and what is its SI unit?

Answer

Electric current is defined as the amount of charge flowing through a cross-section per unit time. I = q/t. The SI unit is ampere (A). 1 ampere = 1 coulomb/second. Current can range from nanoamperes (

Card 2Electric Current

What is the sign convention for electric current direction?

Answer

By convention, the direction of current is taken as the direction in which positive charges would move, even though in metallic conductors, it is actually electrons (negative charges) that move in the

Card 3Drift Velocity

Define drift velocity and derive its relation with current.

Answer

Drift velocity (Vd) is the average velocity with which free electrons move in a conductor under the influence of an electric field. Derivation: For a conductor with length L, cross-sectional area A, a

Card 4Drift Velocity

A metallic wire of diameter 0.02m has 10²⁸ free electrons per m³. Find drift velocity for current of 100A. (e = 1.6 × 10⁻¹⁹ C)

Answer

Given: D = 0.02m, r = 0.01m, n = 10²⁸ electrons/m³, I = 100A, e = 1.6 × 10⁻¹⁹ C Solution: A = πr² = 3.142 × (0.01)² = 3.142 × 10⁻⁴ m² Vd = I/(nAe) = 100/(3.142 × 10⁻⁴ × 10²⁸ × 1.6 × 10⁻¹⁹) = 100/(5.02

Card 5Ohm's Law

State Ohm's law and write its mathematical expression.

Answer

Ohm's law states: 'The current through a conductor is directly proportional to the potential difference applied across its ends, provided the physical state of the conductor remains unchanged.' Mathem

Card 6Resistance and Conductance

What is resistance and conductance? Give their units.

Answer

Resistance (R) is the opposition offered by a conductor to the flow of current. R = V/I. Unit: ohm (Ω). 1Ω = 1V/1A. Conductance (C) is the reciprocal of resistance. C = 1/R. Unit: siemens (S) or (Ω)⁻¹

Card 7Ohm's Law

A flashlight uses two 1.5V batteries to provide 0.5A current. Find the resistance of the filament.

Answer

Given: Total voltage V = 2 × 1.5V = 3.0V, Current I = 0.5A Solution: Using Ohm's law, R = V/I = 3.0V/0.5A = 6.0Ω Therefore, resistance of the glowing filament = 6.0Ω

Card 8Resistivity

Derive the microscopic form of Ohm's law and explain resistivity.

Answer

For an electron in electric field E: Force F = eE, acceleration a = eE/m. If τ is average time between collisions, drift velocity Vd = aτ = (eEτ/m). From Vd = J/(ne), we get J/(ne) = (eEτ/m), which gi

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