Skip to main content
Chapter 5 of 14
Flashcards

Gravitation

Maharashtra Board · Class 11 · Physics

Flashcards for Gravitation — Maharashtra Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions24 flashcards5 concepts
24 Flashcards
Card 1Universal Law of Gravitation

State Newton's Universal Law of Gravitation and write its mathematical expression.

Answer

Newton's Universal Law of Gravitation: Every particle of matter attracts every other particle with a force directly proportional to the product of their masses and inversely proportional to the square

Card 2Kepler's Laws

State Kepler's First Law of Planetary Motion with an example.

Answer

Kepler's First Law (Law of Orbit): All planets move in elliptical orbits around the Sun with the Sun at one of the foci of the ellipse. Key Terms: - Perihelion: Closest point to the Sun - Aphelion: F

Card 3Kepler's Laws

What is Kepler's Second Law? Explain its physical significance.

Answer

Kepler's Second Law (Law of Areas): The line joining a planet and the Sun sweeps equal areas in equal intervals of time. Physical Significance: - Planets move faster when closer to the Sun - Planets

Card 4Kepler's Laws

State Kepler's Third Law and solve: If Earth's orbital period is 1 year, what would be the period if Earth-Sun distance becomes 4 times?

Answer

Kepler's Third Law (Law of Periods): The square of the period of revolution is proportional to the cube of the semi-major axis. T² ∝ r³ or T²/r³ = constant Solution: Given: T₁ = 1 year, r₂ = 4r₁ Us

Card 5Acceleration due to Gravity

Define acceleration due to gravity and derive its expression in terms of Earth's mass and radius.

Answer

Acceleration due to gravity (g): The acceleration experienced by a freely falling body near Earth's surface due to gravitational attraction. Derivation: For a body of mass m at Earth's surface: Gravi

Card 6Variation of g

How does acceleration due to gravity vary with altitude? Derive the expression for gh.

Answer

Variation with Altitude: At height h above Earth's surface: gh = GM/(R+h)² Relation with surface gravity: gh/g = R²/(R+h)² Therefore: gh = g[R²/(R+h)²] For small heights (h << R): gh ≈ g(1 - 2h/R)

Card 7Variation of g

Calculate the value of g at height 320 km above Earth's surface. Given: R = 6400 km, g = 9.8 m/s².

Answer

Given: - h = 320 km = 3.2×10⁵ m - R = 6400 km = 6.4×10⁶ m - g = 9.8 m/s² Since h << R, we can use: gh = g(1 - 2h/R) Substituting values: gh = 9.8(1 - 2×320/6400) gh = 9.8(1 - 640/6400) gh = 9.8(1 -

Card 8Variation of g

How does acceleration due to gravity vary with depth below Earth's surface? Derive the expression.

Answer

Variation with Depth: At depth d below Earth's surface: gd = g(1 - d/R) Derivation: - Only the inner sphere of radius (R-d) contributes to gravity - Outer spherical shell has no net effect - Mass of

+16 more flashcards available

Practice All

Get detailed flashcards for Gravitation

Super Tutor gives you interactive content for every chapter of Maharashtra Board Class 11 Physics — summaries, quizzes, flashcards, and more.

Try Super Tutor — It's Free

Frequently Asked Questions

What are the important topics in Gravitation for Maharashtra Board Class 11 Physics?

Gravitation covers several key topics that are frequently asked in Maharashtra Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 24 flashcards for Gravitation covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.