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Chapter 14 of 16
Flashcards

Probability Distributions

Maharashtra Board · Class 12 · Mathematics & Statistics

Flashcards for Probability Distributions — Maharashtra Board Class 12 Mathematics & Statistics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts
20 Flashcards
Card 1Random Variables

What is a random variable? Provide the formal definition.

Answer

A random variable is a real-valued function defined on the sample space of a random experiment. Domain: Sample space S, Co-domain: Real numbers R. Written as X : S → R. It assigns a unique real number

Card 2Random Variables

A coin is tossed 3 times. Define X = number of heads. Find all possible values of X and their corresponding outcomes.

Answer

Sample space S = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} Possible values of X: {0, 1, 2, 3} [X = 0] = {TTT} [X = 1] = {HTT, THT, TTH} [X = 2] = {HHT, HTH, THH} [X = 3] = {HHH} This shows X is a discr

Card 3Types of Random Variables

What is the difference between discrete and continuous random variables?

Answer

Discrete Random Variable: • Finite or countably infinite values • Values obtained by counting • Examples: Number of students, dice outcomes Continuous Random Variable: • Uncountably infinite values f

Card 4Probability Mass Function

Define Probability Mass Function (p.m.f.) for a discrete random variable.

Answer

For discrete random variable X with possible values x₁, x₂, x₃, ... and probabilities p₁, p₂, p₃, ... The p.m.f. f(x) satisfies: 1. pᵢ ≥ 0 for all i 2. Σpᵢ = 1 3. pᵢ = P[X = xᵢ] = f(xᵢ) The p.m.f. g

Card 5Probability Distribution

Two dice are thrown. Find the probability distribution of X = sum of numbers on dice.

Answer

Sample space: 36 equally likely outcomes Possible values of X: {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} P(X=2) = 1/36, P(X=3) = 2/36, P(X=4) = 3/36 P(X=5) = 4/36, P(X=6) = 5/36, P(X=7) = 6/36 P(X=8) = 5/

Card 6Cumulative Distribution Function

What is the Cumulative Distribution Function (c.d.f.) for a discrete random variable?

Answer

The c.d.f. F(x) of discrete random variable X is: F(x) = P[X ≤ x] = Σ(xᵢ≤x) P[X = xᵢ] Properties: • F(x) is non-decreasing • 0 ≤ F(x) ≤ 1 • F(-∞) = 0, F(∞) = 1 • F(x) is a step function for discrete

Card 7Expected Value

Define Expected Value (Mean) of a discrete random variable and provide the formula.

Answer

Expected Value E(X) or μ is the weighted average of all possible values: E(X) = μ = Σᵢ₌₁ⁿ xᵢpᵢ = x₁p₁ + x₂p₂ + ... + xₙpₙ where xᵢ are possible values and pᵢ are corresponding probabilities. It rep

Card 8Expected Value

A fair die is thrown. Find E(X) where X is the number on the uppermost face.

Answer

Step 1: Identify possible values and probabilities X can take values: 1, 2, 3, 4, 5, 6 Each with probability: 1/6 Step 2: Apply formula E(X) = Σᵢ₌₁⁶ i × (1/6) E(X) = (1 + 2 + 3 + 4 + 5 + 6) × (1/6) E

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Probability Distributions covers several key topics that are frequently asked in Maharashtra Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

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