Maharashtra Board Class 12 Physics — Flashcards for Quick Revision

A: Circular motion is the motion of an object along a circular path. Revolution: The object (or every particle in the object) undergoes circular motion about some point outside the object or about anothe

A: v = ωr (magnitude) v⃗ = ω⃗ × r⃗ (vector form) Where: v = tangential velocity, ω = angular velocity, r = radius Direction of ω is given by right-hand thumb rule along the axis of rotation.

A: Centripetal acceleration is the acceleration directed towards the center of circular motion, responsible for changing the direction of velocity. Derivation: For UCM, speed is constant but direction c

A: A fluid is any substance that can flow and deforms continually under external force. Key characteristics: 1) Shear modulus is zero 2) Cannot resist shear stress 3) Takes shape of container 4) Includes

A: 1) Incompressible: density is constant 2) Irrotational flow: smooth flow without turbulence 3) Non-viscous: no internal friction 4) Steady flow: velocity at each point is constant in time. Real fluids

A: Pressure is the normal force exerted by a fluid per unit area. Formula: P = F/A, where F is force and A is area. SI unit: N/m² = Pascal (Pa). Dimension: [L⁻¹M¹T⁻²]. Other units: bar, torr, mmHg.

A: The ideal gas equation has three forms: 1. PV = nRT (using moles) 2. PV = NkBT (using molecules) 3. PV/T = constant (for fixed mass) Symbols: P = pressure, V = volume, T = absolute temperature n = nu

A: Mean free path (λ) is the average distance traveled by a molecule between two successive collisions. Derivation: - Higher density → more collisions → smaller λ - Larger molecular diameter → more coll

A: Given: T = 273 K, P = 1.01 × 10⁵ Pa d = 324 × 10⁻¹² m Solution: Using λ = kBT/(√2πd²P) λ = (1.38 × 10⁻²³ × 273)/(√2π × (324 × 10⁻¹²)² × 1.01 × 10⁵) λ = (3.76 × 10⁻²¹)/(4.7 × 10⁻¹⁴) λ = 8.0 × 10⁻⁸