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Chapter 12 of 16
Flashcards

Electromagnetic Induction

Maharashtra Board · Class 12 · Physics

Flashcards for Electromagnetic Induction — Maharashtra Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions23 flashcards5 concepts
23 Flashcards
Card 1Faraday's Laws

State Faraday's First Law of Electromagnetic Induction.

Answer

Whenever there is a change of magnetic flux in a closed circuit, an induced EMF is produced in the circuit. Also, if a conductor cuts the lines of magnetic field, an EMF is induced between its ends. T

Card 2Faraday's Laws

Write the mathematical expression for Faraday's Second Law and explain its significance.

Answer

e = -dφ/dt, where e is induced EMF, φ is magnetic flux, and t is time. The negative sign incorporates Lenz's law. For a coil of N turns: e = -N(dφ'/dt). This quantitative law gives the magnitude of in

Card 3Lenz's Law

What is Lenz's Law and how does it relate to energy conservation?

Answer

Lenz's Law: The direction of induced current is such that the magnetic field produced by it opposes the change in magnetic flux that induces the current. This follows from energy conservation - if ind

Card 4Magnetic Flux

Define magnetic flux and write its mathematical expression.

Answer

Magnetic flux through a surface is the measure of magnetic field lines passing through that surface. For a small area: dφ = B⃗ · da⃗ = B da cos θ. For finite area: φ = ∫ B⃗ · da⃗. Unit: Weber (Wb). It

Card 5Motional EMF

A conducting rod of length 0.5 m moves with velocity 10 m/s perpendicular to a magnetic field of 0.2 T. Calculate the induced EMF.

Answer

Given: l = 0.5 m, v = 10 m/s, B = 0.2 T, θ = 90° Formula: e = Blv sin θ Solution: e = 0.2 × 0.5 × 10 × sin 90° e = 0.2 × 0.5 × 10 × 1 = 1.0 V The induced EMF is 1.0 V.

Card 6Motional EMF

Derive the formula for motional EMF in a rotating rod.

Answer

For a rod of length l rotating with angular velocity ω in perpendicular magnetic field B: Consider element dr at distance r: de = Bv dr = Bωr dr Total EMF: e = ∫₀ˡ Bωr dr = Bω ∫₀ˡ r dr = Bω[r²/2]₀ˡ Th

Card 7Self-Inductance

What is self-inductance? Give its definition and unit.

Answer

Self-inductance (L) is the property of a coil by which it opposes changes in current through itself. Definition: L = φ/i (flux per unit current) or L = |e|/(di/dt) (EMF per unit rate of change of curr

Card 8Self-Inductance

Derive the formula for self-inductance of a solenoid.

Answer

For a solenoid: B = μ₀ni (inside), where n = N/l Flux per turn: φ' = BA = μ₀niA Total flux linkage: Nφ' = N × μ₀(N/l)iA = μ₀N²iA/l Self-inductance: L = Nφ'/i = μ₀N²A/l For unit length: L/l = μ₀n²A = μ

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Frequently Asked Questions

What are the important topics in Electromagnetic Induction for Maharashtra Board Class 12 Physics?

Electromagnetic Induction covers several key topics that are frequently asked in Maharashtra Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

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