Skip to main content
Chapter 13 of 14
Flashcards

Gravitation

Madhya Pradesh Board · Class 11 · Physics

Flashcards for Gravitation — Madhya Pradesh Board Class 11 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

62 questions22 flashcards5 concepts
22 Flashcards
Card 1Universal Law of Gravitation

What is Newton's Universal Law of Gravitation? State it mathematically.

Answer

Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

Card 2Kepler's Laws

State Kepler's First Law of Planetary Motion.

Answer

Law of Orbits: All planets move in elliptical orbits with the Sun situated at one of the foci of the ellipse. Key points: - Planets follow elliptical paths, not circular ones - The Sun is located at

Card 3Kepler's Laws

What is Kepler's Second Law? Why does it occur?

Answer

Law of Areas: The line that joins any planet to the Sun sweeps equal areas in equal intervals of time. Why it occurs: - This law is a consequence of conservation of angular momentum - Gravitational f

Card 4Kepler's Laws

State Kepler's Third Law and write its mathematical expression.

Answer

Law of Periods: The square of the time period of revolution of a planet is proportional to the cube of the semi-major axis of the ellipse traced out by the planet. Mathematically: T² ∝ a³ Or: T² = (4

Card 5Gravitational Constant

What is the value of the universal gravitational constant G? Who first measured it?

Answer

Value: G = 6.67 × 10⁻¹¹ N m²/kg² First measured by: Henry Cavendish in 1798 Cavendish's experiment: - Used a torsion balance with lead spheres - Measured the tiny gravitational attraction between ma

Card 6Acceleration due to Gravity

Derive the expression for acceleration due to gravity on Earth's surface.

Answer

For a mass m on Earth's surface: - Gravitational force: F = GMₑm/Rₑ² - From Newton's second law: F = mg Therefore: mg = GMₑm/Rₑ² Canceling m: g = GMₑ/Rₑ² Where: - g = acceleration due to gravity (≈

Card 7Variation of Gravity

How does acceleration due to gravity vary with height above Earth's surface?

Answer

At height h above Earth's surface: g(h) = GMₑ/(Rₑ + h)² For small heights (h << Rₑ): g(h) ≈ g(1 - 2h/Rₑ) Key points: - Gravity decreases with height - For small heights, decrease is approximately l

Card 8Variation of Gravity

How does acceleration due to gravity vary with depth below Earth's surface?

Answer

At depth d below Earth's surface: g(d) = g(1 - d/Rₑ) Key points: - Gravity decreases linearly with depth - At Earth's center (d = Rₑ), gravity becomes zero - Only the inner sphere of radius (Rₑ - d)

+14 more flashcards available

Practice All

Get detailed flashcards for Gravitation

Super Tutor gives you interactive content for every chapter of Madhya Pradesh Board Class 11 Physics — summaries, quizzes, flashcards, and more.

Try Super Tutor — It's Free

Frequently Asked Questions

What are the important topics in Gravitation for Madhya Pradesh Board Class 11 Physics?

Gravitation covers several key topics that are frequently asked in Madhya Pradesh Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 22 flashcards for Gravitation covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.