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Moving Charges and Magnetism

Madhya Pradesh Board · Class 12 · Physics

Flashcards for Moving Charges and Magnetism — Madhya Pradesh Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.

30 questions22 flashcards5 concepts
22 Flashcards
Card 1Magnetic Force

What is the Lorentz force? Write its mathematical expression and explain each term.

Answer

The Lorentz force is the total force experienced by a charged particle in the presence of both electric and magnetic fields. F = q(E + v × B) Where: - F = Total force on the charge - q = Charge of t

Card 2Magnetic Force

State three key characteristics of magnetic force on a moving charged particle.

Answer

1. **Velocity dependence**: Force exists only when the charge is moving (|v| ≠ 0) 2. **Perpendicular direction**: Magnetic force is always perpendicular to both velocity (v) and magnetic field (B) 3

Card 3Magnetic Field

What is the SI unit of magnetic field? Define it based on the force equation.

Answer

The SI unit of magnetic field is **Tesla (T)**. Definition: 1 Tesla is the magnetic field strength when a charge of 1 coulomb moving with velocity 1 m/s perpendicular to the field experiences a force

Card 4Current and Magnetism

Derive the expression for the force on a current-carrying conductor in a magnetic field.

Answer

For a straight conductor of length l carrying current I: Starting from microscopic level: - Number of charge carriers = nlA (n = number density, A = cross-section) - Each carrier has charge q and dri

Card 5Motion in Magnetic Field

A charged particle moves in a uniform magnetic field. Describe its motion when v ⊥ B and when v has components both parallel and perpendicular to B.

Answer

**Case 1: v ⊥ B (velocity perpendicular to field)** - Particle follows a circular path - Magnetic force provides centripetal force - Radius: r = mv/(qB) - Frequency: ν = qB/(2πm) (cyclotron frequency)

Card 6Biot-Savart Law

State the Biot-Savart Law and explain its significance.

Answer

**Biot-Savart Law**: The magnetic field dB due to a current element Idl at distance r is: **dB = (μ₀/4π) × (Idl × r)/r³** Where: - μ₀ = 4π × 10⁻⁷ Tm/A (permeability of free space) - dl = current ele

Card 7Circular Current Loop

Find the magnetic field at the center of a circular current loop of radius R carrying current I.

Answer

For a circular loop at the center (x = 0): Using Biot-Savart law: - Each element dl is perpendicular to r - All elements are at same distance R from center - All dB vectors point in same direction (p

Card 8Ampere's Law

State Ampere's Circuital Law and explain when it can be applied easily.

Answer

**Ampere's Circuital Law**: ∮ B⃗ · dl⃗ = μ₀Iₑₙcₗₒₛₑd The line integral of magnetic field around any closed path equals μ₀ times the net current enclosed by that path. **Easy Application Conditions**

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