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Chapter 13 of 14
Flashcards

Statistics

Rajasthan Board · Class 11 · Mathematics

Flashcards for Statistics — Rajasthan Board Class 11 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

104 questions20 flashcards5 concepts
20 Flashcards
Card 1Introduction to Dispersion

What is the limitation of measures of central tendency in analyzing data?

Answer

Measures of central tendency (mean, median, mode) only give information about where data points are centered. They do not tell us how the data is scattered or spread around this central value. For exa

Card 2Range

Define Range and write its formula.

Answer

Range is the simplest measure of dispersion that shows the difference between the maximum and minimum values in a dataset. Formula: Range = Maximum value - Minimum value Example: For data 10, 15, 20

Card 3Range

What is the main limitation of Range as a measure of dispersion?

Answer

Range only considers the extreme values (maximum and minimum) and ignores all other observations in the dataset. It does not provide information about how data is distributed around the central tenden

Card 4Mean Deviation

Why do we take absolute values when calculating mean deviation?

Answer

We take absolute values because: 1. The sum of deviations from mean is always zero (positive and negative deviations cancel out) 2. Absolute values ensure all deviations are positive 3. This gives us

Card 5Mean Deviation

Write the formula for Mean Deviation about mean for ungrouped data.

Answer

Mean Deviation about mean = (1/n) × Σ|xi - x̄| Where: - n = number of observations - xi = individual observations - x̄ = mean of the data - |xi - x̄| = absolute deviation from mean Steps: 1) Find me

Card 6Mean Deviation

Write the formula for Mean Deviation about median for ungrouped data.

Answer

Mean Deviation about median = (1/n) × Σ|xi - M| Where: - n = number of observations - xi = individual observations - M = median of the data - |xi - M| = absolute deviation from median Note: Mean dev

Card 7Mean Deviation

Calculate mean deviation about mean for data: 6, 7, 10, 12, 13, 4, 8, 12

Answer

Step 1: Find mean = (6+7+10+12+13+4+8+12)/8 = 72/8 = 9 Step 2: Find deviations from mean: |6-9|=3, |7-9|=2, |10-9|=1, |12-9|=3 |13-9|=4, |4-9|=5, |8-9|=1, |12-9|=3 Step 3: Sum of absolute deviations

Card 8Mean Deviation

Write the formula for Mean Deviation for grouped data (discrete frequency distribution).

Answer

Mean Deviation about mean = (1/N) × Σfi|xi - x̄| Mean Deviation about median = (1/N) × Σfi|xi - M| Where: - N = Σfi (total frequency) - fi = frequency of each class - xi = value or class mark - x̄ =

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Frequently Asked Questions

What are the important topics in Statistics for Rajasthan Board Class 11 Mathematics?

Statistics covers several key topics that are frequently asked in Rajasthan Board Class 11 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

There are 20 flashcards for Statistics covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.