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MHT-CET Rank Predictor 2026

Predict your MHT-CET rank from your percentile score. Uses the formula: Rank = ((100 − Percentile) / 100) × Total Candidates. Separate calculations for PCM and PCB groups.

Predict Your MHT-CET Rank

Total candidates (PCM (Engineering)): 5,50,000

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MHT-CET Percentile to Rank Table (2025)

PercentilePCM RankPCB Rank
99.91 – 551 – 48
99.5250 – 275220 – 240
99500 – 550440 – 480
981,000 – 1,100880 – 960
952,500 – 2,7502,200 – 2,400
905,000 – 5,5004,400 – 4,800
8010,000 – 11,0008,800 – 9,600
7015,000 – 16,50013,200 – 14,400
5025,000 – 27,50022,000 – 24,000

Frequently Asked Questions

How is MHT-CET rank calculated from percentile?

MHT-CET rank is calculated using the formula: Rank = ((100 - Percentile) / 100) × Total Candidates in your group. The exam has separate percentile calculations for PCM and PCB groups. Approximately 5.5 lakh students appear for PCM and 4.8 lakh for PCB.

For COEP Pune (College of Engineering Pune) CSE branch, you typically need a MHT-CET percentile of 99+ (rank under 500). For other branches like Mechanical or Civil, a percentile of 95-98 may be sufficient. Cutoffs vary by category and round.

Yes, with 80 percentile in MHT-CET you can get admission in many good private engineering colleges in Maharashtra. For government colleges, you may get seats in newer colleges or less popular branches. Your rank would be approximately 10,000-11,000.

MHT-CET is generally considered easier than JEE Main in terms of difficulty level. It is based on Maharashtra State Board (HSC) syllabus, while JEE Main covers a broader syllabus. However, competition is intense as it is the primary exam for Maharashtra engineering admissions.