Molarity Calculator
Calculate molarity (M), moles, or volume of a solution using the formula M = n / V. Enter any two known values to find the third. Essential for stoichiometry and titration problems in CBSE, JEE, and NEET Chemistry.
Molarity Calculator
Molarity (M)
1 M
M = 0.5 mol ÷ 0.5 L = 1 M
Quick Reference
0.5 mol of NaCl (58.44 g/mol) = 29.22 g
Use the Molar Mass Calculator for other compounds.
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Example 1 — Find Molarity:
0.5 mol NaCl in 250 mL → M = 0.5 ÷ 0.25 = 2 M
Example 2 — Find Moles:
0.1 M HCl, 500 mL → n = 0.1 × 0.5 = 0.05 mol
Example 3 — Find Volume:
Need 0.2 mol NaOH at 1 M → V = 0.2 ÷ 1 = 0.2 L = 200 mL
Frequently Asked Questions
What is molarity and how is it calculated?
Molarity (M) is the number of moles of solute per litre of solution. Formula: M = n / V, where n = moles of solute and V = volume of solution in litres. For example, dissolving 0.5 moles of NaCl in 1 L of water gives a 0.5 M solution.
What is the difference between molarity and molality?
Molarity (M) = moles of solute ÷ litres of solution. Molality (m) = moles of solute ÷ kilograms of solvent. Molarity changes with temperature (since volume changes), but molality does not. JEE often tests this distinction.
How do I convert mass to moles for molarity calculations?
Divide the mass of solute (in grams) by its molar mass (in g/mol). For example, 58.44 g of NaCl has a molar mass of 58.44 g/mol, so it contains 1 mole. Use our Molar Mass Calculator to find the molar mass of any compound.
What are common molarity values used in labs and exams?
Common concentrations include: 0.1 M HCl (dilute acid), 1 M NaOH (standard base), 0.01 M KMnO₄ (titration standard), 18 M H₂SO₄ (concentrated acid). CBSE Class 12 and JEE problems frequently use these values.