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Quadratic Equation Solver

Solve any quadratic equation of the form ax² + bx + c = 0. Enter coefficients a, b, and c to get roots, discriminant, nature of roots, vertex, and step-by-step solution.

Enter Coefficients

1x² + -5x + 6 = 0

Roots of the Equation

x₁ = 3, x₂ = 2

Discriminant D = 1

Nature of Roots

Two distinct real roots (D > 0)

Discriminant (D)

1

D = b² − 4ac = 2524

Sum of Roots (−b/a)

5

Product of Roots (c/a)

6

Vertex

(2.5, -0.25)

Parabola opens upward

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How to Solve a Quadratic Equation

x = (−b ± √(b² − 4ac)) / 2a

Step 1: Write the equation in standard form: ax² + bx + c = 0

Step 2: Calculate the discriminant: D = b² − 4ac

Step 3: Apply the quadratic formula to find roots

Example: x² − 5x + 6 = 0 → a=1, b=−5, c=6

  • D = (−5)² − 4(1)(6) = 25 − 24 = 1
  • x = (5 ± √1) / 2 = (5 ± 1) / 2
  • x₁ = 3, x₂ = 2

Frequently Asked Questions

What is the quadratic formula?

The quadratic formula is x = (−b ± √(b² − 4ac)) / 2a. It gives the roots (solutions) of any quadratic equation ax² + bx + c = 0, where a ≠ 0.

The discriminant D = b² − 4ac determines the nature of roots. If D > 0, the equation has two distinct real roots. If D = 0, it has two equal real roots (one repeated root). If D < 0, it has two complex (imaginary) roots.

In CBSE Class 10 Maths Chapter 4, you learn three methods: factorisation, completing the square, and the quadratic formula. For board exams, show all steps — write the standard form, calculate the discriminant, then apply the formula.

Yes. When the discriminant (b² − 4ac) is negative, the roots are complex numbers involving i (the imaginary unit, where i² = −1). This is covered in Class 11 Maths (Complex Numbers chapter) and is important for JEE preparation.