Current Electricity
Karnataka Board · Class 12 · Physics
Flashcards for Current Electricity — Karnataka Board Class 12 Physics. Quick Q&A cards covering key concepts, definitions, and formulas.
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See them allWhat is electric current? Give its SI unit and definition.
Answer
Electric current is the net amount of charge flowing across a cross-section per unit time. It is defined as I = Q/t, where Q is charge and t is time. The SI unit is ampere (A). For varying current: I(…
State Ohm's Law and write its mathematical expression.
Answer
Ohm's Law states that the potential difference (V) across a conductor is directly proportional to the current (I) flowing through it, provided temperature and other physical conditions remain constant…
How does resistance depend on the dimensions of a conductor? Derive the relationship.
Answer
Resistance is directly proportional to length (l) and inversely proportional to cross-sectional area (A): R = ρl/A, where ρ is resistivity. When length doubles, resistance doubles (R ∝ l). When area h…
Define resistivity and conductivity. How are they related?
Answer
Resistivity (ρ) is a material property that opposes current flow, with SI unit Ω⋅m. It's given by ρ = RA/l. Conductivity (σ) is the reciprocal of resistivity: σ = 1/ρ, with SI unit S/m (siemens per me…
What is drift velocity? Derive the expression for current in terms of drift velocity.
Answer
Drift velocity (vd) is the average velocity of charge carriers in a conductor under an electric field. For current: I = nAevd, where n is number density of charge carriers, A is cross-sectional area, …
Derive the relationship between drift velocity and electric field.
Answer
Under electric field E, electrons experience acceleration a = -eE/m. After average collision time τ, drift velocity is: vd = -eEτ/m. The magnitude is |vd| = eEτ/m. This shows drift velocity is proport…
What is mobility? Write its formula and SI unit.
Answer
Mobility (μ) is the magnitude of drift velocity per unit electric field: μ = |vd|/E. From drift velocity formula: μ = eτ/m, where τ is relaxation time and m is mass of charge carrier. SI unit is m²/(V…
Derive the microscopic form of Ohm's Law and express conductivity in terms of microscopic parameters.
Answer
From j = nevd and vd = eEτ/m, we get j = (ne²τ/m)E. Comparing with j = σE, conductivity is: σ = ne²τ/m. Since ρ = 1/σ, resistivity is: ρ = m/(ne²τ). This connects macroscopic properties to microscopic…
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Sources & Official References
- Karnataka SSLC — kseeb.kar.nic.in
- Dept of Pre-University Education, Karnataka
- National Education Policy 2020 — education.gov.in
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