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Application of Integrals

Kerala Board · Class 12 · Mathematics

Flashcards for Application of Integrals — Kerala Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

32 questions20 flashcards5 concepts

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An illustration showing a curve y=f(x) bounded by the x-axis and vertical lines x=a and x=b. The area is approximated by numerous thin vertical rectangular strips, with one representative strip highli
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20 Flashcards
Card 1Area under curves

What is the basic formula for finding the area under a curve y = f(x) between x = a and x = b?

Answer

Area = ∫[a to b] f(x) dx, where the curve is above the x-axis. This represents the sum of infinitely many thin rectangular strips of width dx and height y = f(x).

Card 2Area under curves

How do you find the area of a region bounded by x = g(y), y-axis, and lines y = c and y = d?

Answer

Area = ∫[c to d] g(y) dy. Here we use horizontal strips instead of vertical strips, integrating with respect to y from y = c to y = d.

Card 3Area under curves

What is an elementary area strip and how is it represented mathematically?

Answer

An elementary area strip is a thin vertical rectangle of height y and width dx. Its area is dA = y dx = f(x) dx. The total area is found by summing all such strips using integration.

Card 4Area under curves

What happens when the curve y = f(x) lies below the x-axis?

Answer

When f(x) < 0, the integral ∫[a to b] f(x) dx gives a negative value. Since area is always positive, we take the absolute value: Area = |∫[a to b] f(x) dx|.

Card 5Area under curves

How do you find the area when part of the curve is above x-axis and part is below?

Answer

Split the region at points where the curve crosses the x-axis. Calculate area for each part separately and add their absolute values: Total Area = |A₁| + |A₂| + ... where each Aᵢ represents area of on

Card 6Area calculations

Find the area bounded by y = x², x-axis, and lines x = 1 and x = 3.

Answer

Area = ∫[1 to 3] x² dx = [x³/3]₁³ = (27/3) - (1/3) = 9 - 1/3 = 26/3 square units.

Card 7Area calculations

What is the area bounded by y = √x, x-axis, and lines x = 0 and x = 4?

Answer

Area = ∫[0 to 4] √x dx = ∫[0 to 4] x^(1/2) dx = [2x^(3/2)/3]₀⁴ = (2/3)(4)^(3/2) = (2/3)(8) = 16/3 square units.

Card 8Area between curves

How do you find the area between two curves y = f(x) and y = g(x) from x = a to x = b?

Answer

If f(x) ≥ g(x) in the interval [a,b], then Area = ∫[a to b] [f(x) - g(x)] dx. Always subtract the lower curve from the upper curve.

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What are the important topics in Application of Integrals for Kerala Board Class 12 Mathematics?
Application of Integrals covers several key topics that are frequently asked in Kerala Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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