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Solutions

CBSE · Class 12 · Chemistry

Flashcards for Solutions — CBSE Class 12 Chemistry. Quick Q&A cards covering key concepts, definitions, and formulas.

70 questions20 flashcards5 concepts
20 Flashcards
Card 1Types of Solutions

Define a solution and classify the different types based on physical states of solute and solvent.

Answer

A solution is a homogeneous mixture of two or more components with uniform composition and properties throughout. Types: Gaseous solutions (O₂ + N₂), Liquid solutions (glucose in water), Solid solutio

Card 2Concentration Units

Calculate the mass percentage of NaCl in a solution containing 20g NaCl dissolved in 180g water.

Answer

Formula: Mass % = (Mass of component/Total mass) × 100 Step 1: Total mass = 20g + 180g = 200g Step 2: Mass % of NaCl = (20/200) × 100 = 10% Answer: 10% by mass

Card 3Henry's Law

State Henry's Law and write its mathematical expression. Give one practical application.

Answer

Henry's Law: At constant temperature, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the solution. Mathematical form: p = KH × x Where p = partia

Card 4Concentration Units

Calculate molality of a solution containing 5.85g NaCl (M = 58.5 g/mol) dissolved in 500g water.

Answer

Formula: Molality (m) = moles of solute/kg of solvent Step 1: Moles of NaCl = 5.85/58.5 = 0.1 mol Step 2: Mass of water = 500g = 0.5 kg Step 3: Molality = 0.1/0.5 = 0.2 m Answer: 0.2 molal

Card 5Raoult's Law

What is Raoult's Law? Write its equation for binary liquid solutions and explain ideal solutions.

Answer

Raoult's Law: The partial vapour pressure of each component in solution is directly proportional to its mole fraction. For binary solutions: p₁ = p₁⁰ × x₁ and p₂ = p₂⁰ × x₂ Total pressure: ptotal = p₁

Card 6Concentration Units

Calculate mole fraction of ethanol in a solution containing 46g ethanol (C₂H₅OH, M = 46 g/mol) and 54g water (M = 18 g/mol).

Answer

Step 1: Moles of ethanol = 46/46 = 1 mol Step 2: Moles of water = 54/18 = 3 mol Step 3: Total moles = 1 + 3 = 4 mol Step 4: Mole fraction of ethanol = 1/4 = 0.25 Answer: 0.25

Card 7Non-ideal Solutions

Why do non-ideal solutions show positive deviation from Raoult's Law? Give an example with explanation.

Answer

Positive deviation occurs when A-B interactions are weaker than A-A and B-B interactions. This makes molecules easier to escape, increasing vapour pressure above ideal value. Example: Ethanol + Aceton

Card 8Colligative Properties

What are colligative properties? List all four with their definitions.

Answer

Colligative properties depend only on number of solute particles, not their nature. 1. Relative lowering of vapour pressure: (p₁⁰-p₁)/p₁⁰ = x₂ 2. Elevation of boiling point: ΔTb = Kb×m 3. Depression o

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What are the important topics in Solutions for CBSE Class 12 Chemistry?

Solutions covers several key topics that are frequently asked in CBSE Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.

Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.

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Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.