Differentiation Of Trigonometric Functions
Telangana Board · Class 12 · Mathematics
Summary of Differentiation Of Trigonometric Functions for Telangana Board Class 12 Mathematics. Key concepts, important points, and chapter overview.
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Overview
This chapter explores the differentiation of trigonometric and inverse trigonometric functions, building upon fundamental calculus concepts. We learn to find derivatives using first principles and apply various differentiation rules including product, quotient, and chain rules. Understanding these d
Key Concepts
The fundamental derivatives
The fundamental derivatives are: d/dx(sin x) = cos x, d/dx(cos x) = -sin x, d/dx(tan x) = sec²x, d/dx(cot x) = -csc²x, d/dx(sec x) = sec x tan x, d/dx
For composite functions like sin(u)
For composite functions like sin(u), where u = f(x), the derivative is d/dx[sin u] = cos u × du/dx. This extends to all trigonometric functions: d/dx[
Key derivatives include
Key derivatives include: d/dx(sin⁻¹x) = 1/√(1-x²), d/dx(cos⁻¹x) = -1/√(1-x²), d/dx(tan⁻¹x) = 1/(1+x²), d/dx(cot⁻¹x) = -1/(1+x²), d/dx(sec⁻¹x) = 1/(|x|
When differentiating products like x sin
When differentiating products like x sin x, use (uv)' = u'v + uv'. For quotients like sin x/cos x, use (u/v)' = (u'v - uv')/v². These rules combined w
The second derivative d²y/dx² is found
The second derivative d²y/dx² is found by differentiating the first derivative. For trigonometric functions: d²/dx²(sin x) = -sin x, d²/dx²(cos x) = -
Learning Objectives
- Find derivatives of trigonometric functions (sin x, cos x, tan x, sec x, csc x, cot x) from first principles
- Apply chain rule to differentiate composite trigonometric functions
- Find derivatives of inverse trigonometric functions using first principles and alternative methods
- Apply product, quotient, and chain rules to complex trigonometric expressions
- Calculate second-order derivatives of trigonometric and inverse trigonometric functions
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