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Chapter 23 of 31
Flashcards

Conic Sections

Telangana Board · Class 12 · Mathematics

Flashcards for Conic Sections — Telangana Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts

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20 Flashcards
Card 1Basic Definitions

What is a conic section? Define focus, directrix, and eccentricity.

Answer

A conic section is the locus of a point P which moves so that its distance from a fixed point is always in a constant ratio to its perpendicular distance from a fixed line. • Focus: The fixed point (

Card 2Parabola

What is the standard equation of a parabola with vertex at origin and axis along x-axis?

Answer

Standard equation: y² = 4ax Key properties: • Vertex: (0, 0) • Focus: (a, 0) • Directrix: x = -a • Axis: y = 0 (x-axis) • Latus rectum: 4a • Opens rightward if a > 0, leftward if a < 0 Derivation: U

Card 3Parabola

Find the equation of parabola with focus (2, 0) and directrix x = -2.

Answer

Step 1: Identify the form Since focus is on x-axis and directrix is vertical, use y² = 4ax Step 2: Find value of 'a' Focus is (a, 0) = (2, 0), so a = 2 Directrix is x = -a = -2 ✓ (matches given) Ste

Card 4Parabola

What are the four standard forms of parabola with vertex at origin?

Answer

1. y² = 4ax (opens right, a > 0) Focus: (a,0), Directrix: x = -a 2. y² = -4ax (opens left, a > 0) Focus: (-a,0), Directrix: x = a 3. x² = 4ay (opens up, a > 0) Focus: (0,a), Directrix: y =

Card 5Parabola

Find the equation of tangent to parabola y² = 12x at point (3, 6).

Answer

Method: Use tangent formula yy₁ = 2a(x + x₁) Step 1: Identify parameters Parabola: y² = 12x = 4(3)x, so a = 3 Point: (x₁, y₁) = (3, 6) Step 2: Verify point lies on parabola 6² = 12(3) → 36 = 36 ✓ S

Card 6Ellipse

What is an ellipse? Define its standard equation and key parameters.

Answer

Ellipse: Locus of point whose distance from fixed point bears constant ratio (e < 1) to distance from fixed line. Standard equation: x²/a² + y²/b² = 1 (a > b) Key parameters: • Semi-major axis: a •

Card 7Ellipse

Find eccentricity and foci of ellipse 4x² + 9y² = 36.

Answer

Step 1: Convert to standard form 4x² + 9y² = 36 Divide by 36: x²/9 + y²/4 = 1 Step 2: Identify a² and b² Comparing with x²/a² + y²/b² = 1: a² = 9, b² = 4 So a = 3, b = 2 (since a > b) Step 3: Find e

Card 8Ellipse

Find equation of ellipse with foci (±4, 0) and eccentricity 1/3.

Answer

Step 1: Use given information Foci: (±ae, 0) = (±4, 0) Eccentricity: e = 1/3 Step 2: Find 'a' ae = 4 and e = 1/3 a × 1/3 = 4 a = 12 Step 3: Find 'b' e² = 1 - b²/a² (1/3)² = 1 - b²/144 1/9 = 1 - b²/1

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Frequently Asked Questions

What are the important topics in Conic Sections for Telangana Board Class 12 Mathematics?
Conic Sections covers several key topics that are frequently asked in Telangana Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Conic Sections — Telangana Board Class 12 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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There are 20 flashcards for Conic Sections covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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