Skip to main content
Chapter 10 of 31
Flashcards

Limits And Continuity

Telangana Board · Class 12 · Mathematics

Flashcards for Limits And Continuity — Telangana Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards5 concepts

Interactive on Super Tutor

Studying Limits And Continuity? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.

1,000+ Class 12 students started this chapter today

20 Flashcards
Card 1Basic Limit Definition

Define the limit of a function f(x) as x approaches a. What are the three conditions that must be satisfied?

Answer

The limit of f(x) as x approaches a is l, written as lim[x→a] f(x) = l, if: 1. f(x) is defined in some neighborhood of a (but not necessarily at a) 2. As x gets arbitrarily close to a from both sides

Card 2Algebraic Limits - Factorization

Solve: lim[x→3] (x² - 9)/(x - 3)

Answer

Step 1: Direct substitution gives 0/0 (indeterminate form) Step 2: Factor the numerator: x² - 9 = (x - 3)(x + 3) Step 3: Simplify: (x² - 9)/(x - 3) = (x - 3)(x + 3)/(x - 3) = x + 3 (for x ≠ 3) Step 4:

Card 3One-sided Limits

What is the difference between left-hand limit and right-hand limit? When do they matter?

Answer

Left-hand limit (LHL): lim[x→a⁻] f(x) - approach a from values less than a Right-hand limit (RHL): lim[x→a⁺] f(x) - approach a from values greater than a Key Point: lim[x→a] f(x) exists only if LHL =

Card 4Standard Limits - Trigonometric

Prove that lim[x→0] (sin x)/x = 1

Answer

Geometric Proof: Step 1: Consider unit circle with angle x (in radians) Step 2: Compare areas: △OAC < sector OAB < △OBD Step 3: Area relationships: (1/2)cos x sin x < x/2 < (1/2)tan x Step 4: Multiply

Card 5Trigonometric Limits

Evaluate: lim[x→0] (1 - cos x)/x²

Answer

Method 1 - Using trigonometric identity: Step 1: Use identity 1 - cos x = 2sin²(x/2) Step 2: lim[x→0] (2sin²(x/2))/x² Step 3: = lim[x→0] 2 × [sin(x/2)/(x/2)]² × (1/4) Step 4: = 2 × (1)² × (1/4) = 1/2

Card 6Rationalization Method

Solve using rationalization: lim[x→0] (√(1+x) - 1)/x

Answer

Step 1: Direct substitution gives 0/0 form Step 2: Rationalize by multiplying by conjugate: = lim[x→0] (√(1+x) - 1)/x × (√(1+x) + 1)/(√(1+x) + 1) Step 3: Numerator becomes: (1+x) - 1 = x Step 4: = lim

Card 7L'Hôpital's Rule

What is L'Hôpital's Rule and when can it be applied?

Answer

L'Hôpital's Rule: If lim[x→a] f(x)/g(x) gives 0/0 or ∞/∞ form, then: lim[x→a] f(x)/g(x) = lim[x→a] f'(x)/g'(x) Conditions for application: 1. f(x) and g(x) are differentiable near x = a 2. lim[x→a] f

Card 8Limits at Infinity

Find: lim[x→∞] (3x² + 2x + 1)/(2x² - x + 5)

Answer

Method: Divide numerator and denominator by highest power of x (x²) Step 1: = lim[x→∞] (3x²/x² + 2x/x² + 1/x²)/(2x²/x² - x/x² + 5/x²) Step 2: = lim[x→∞] (3 + 2/x + 1/x²)/(2 - 1/x + 5/x²) Step 3: As x

+12 more flashcards available

Practice All

Frequently Asked Questions

What are the important topics in Limits And Continuity for Telangana Board Class 12 Mathematics?
Limits And Continuity covers several key topics that are frequently asked in Telangana Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Limits And Continuity — Telangana Board Class 12 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
How many flashcards are available for Limits And Continuity?
There are 20 flashcards for Limits And Continuity covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Limits And Continuity chapter — for free.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for Telangana Board Class 12 Mathematics.