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Chapter 12 of 31
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Differentiation

Telangana Board · Class 12 · Mathematics

Flashcards for Differentiation — Telangana Board Class 12 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions20 flashcards5 concepts

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20 Flashcards
Card 1Basic Definition

What is the definition of derivative of a function f(x) from first principles?

Answer

The derivative of f(x) from first principles is: f'(x) = lim[h→0] [f(x+h) - f(x)]/h This represents the instantaneous rate of change of f(x) with respect to x. The process of finding this derivative

Card 2Geometric Interpretation

What is the geometric interpretation of dy/dx at point P(x,y) on curve y = f(x)?

Answer

Geometric interpretation: dy/dx represents the slope of the tangent line to the curve at point P. Step-by-step understanding: 1. Consider points P(x,y) and Q(x+δx, y+δy) on the curve 2. Slope of seca

Card 3Power Rule

State and prove the Power Rule (Newton's Power Formula): d/dx(xⁿ) = ?

Answer

Power Rule: d/dx(xⁿ) = nxⁿ⁻¹ Proof using first principles: Let y = xⁿ y + δy = (x + δx)ⁿ δy = (x + δx)ⁿ - xⁿ = xⁿ[(1 + δx/x)ⁿ - 1] Using binomial expansion: (1 + δx/x)ⁿ = 1 + n(δx/x) + n(n-1)/2!(

Card 4Applications - Velocity

A car travels distance S = 3t² meters in t seconds. Find its velocity at t = 4 seconds.

Answer

Step-by-step solution: Given: S = 3t² Find: Velocity at t = 4 seconds Step 1: Velocity = dS/dt (derivative of distance) Step 2: Apply power rule to S = 3t² dS/dt = 3 × d/dt(t²) = 3 × 2t = 6t

Card 5Constant Rule

What is the derivative of a constant function? Prove it.

Answer

Derivative of constant: d/dx(c) = 0 Proof: Let y = c (constant) y + δy = c (since c doesn't change with x) δy = c - c = 0 δy/δx = 0/δx = 0 dy/dx = lim[δx→0] (0) = 0 Alternatively using power rule: c

Card 6Sum and Difference Rules

State the Sum Rule and Difference Rule for derivatives with examples.

Answer

Sum Rule: d/dx[f(x) + g(x)] = d/dx[f(x)] + d/dx[g(x)] Difference Rule: d/dx[f(x) - g(x)] = d/dx[f(x)] - d/dx[g(x)] Step-by-step example: Find d/dx(x³ + 2x² - 5x + 7) Step 1: Apply sum/difference rul

Card 7Mixed Functions

Find the derivative of y = x³ + 1/x² - 1/x using appropriate rules.

Answer

Step-by-step solution: Step 1: Rewrite using negative powers y = x³ + x⁻² - x⁻¹ Step 2: Apply sum/difference rule dy/dx = d/dx(x³) + d/dx(x⁻²) - d/dx(x⁻¹) Step 3: Apply power rule to each term • d/

Card 8Product Rule

State the Product Rule for derivatives and solve: d/dx[(x² + 1)(3x - 2)]

Answer

Product Rule: d/dx[f(x)g(x)] = f'(x)g(x) + f(x)g'(x) Or: d/dx(uv) = u'v + uv' Solution for d/dx[(x² + 1)(3x - 2)]: Step 1: Identify functions f(x) = x² + 1, g(x) = 3x - 2 Step 2: Find derivatives f

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What are the important topics in Differentiation for Telangana Board Class 12 Mathematics?
Differentiation covers several key topics that are frequently asked in Telangana Board Class 12 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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