Skip to main content
Chapter 25 of 28
Flashcards

Complementary Angles

ICSE · Class 9 · Mathematics

Flashcards for Complementary Angles — ICSE Class 9 Mathematics. Quick Q&A cards covering key concepts, definitions, and formulas.

44 questions22 flashcards5 concepts

Interactive on Super Tutor

Studying Complementary Angles? Get the full interactive chapter.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.

1,000+ Class 9 students started this chapter today

An illustration showing two acute angles whose sum is 90 degrees, defining them as complementary angles. Examples like 30 and 60 degrees, and a general case with x and (90-x) degrees.
Super Tutor

Learn better with visuals Super Tutor has hundreds of illustrations like this across every chapter — all free to try.

Get started
22 Flashcards
Card 1Basic Definitions

What are complementary angles? Give two examples.

Answer

Two acute angles are said to be complementary if their sum is 90°. Examples: 1. 30° and 60° are complementary (30° + 60° = 90°) 2. 45° and 45° are complementary (45° + 45° = 90°) 3. θ and (90° - θ) a

Card 2Basic Definitions

If an angle measures 35°, what is its complement?

Answer

Complement of 35° = 90° - 35° = 55° General rule: For any angle θ, its complement = (90° - θ)

Card 3Sine-Cosine Relationships

State the relationship between sin θ and cos(90° - θ).

Answer

sin θ = cos(90° - θ) This means: The sine of an angle equals the cosine of its complement. Example: sin 30° = cos 60° = 1/2

Card 4Sine-Cosine Relationships

State the relationship between cos θ and sin(90° - θ).

Answer

cos θ = sin(90° - θ) This means: The cosine of an angle equals the sine of its complement. Example: cos 30° = sin 60° = √3/2

Card 5Applications

What is the value of sin 40°/cos 50°?

Answer

sin 40°/cos 50° = sin 40°/cos(90° - 40°) = sin 40°/sin 40° = 1 Since cos 50° = cos(90° - 40°) = sin 40°

Card 6Tangent-Cotangent Relationships

State the relationship between tan θ and cot(90° - θ).

Answer

tan θ = cot(90° - θ) This means: The tangent of an angle equals the cotangent of its complement. Example: tan 45° = cot 45° = 1

Card 7Tangent-Cotangent Relationships

State the relationship between cot θ and tan(90° - θ).

Answer

cot θ = tan(90° - θ) This means: The cotangent of an angle equals the tangent of its complement. Example: cot 30° = tan 60° = √3

Card 8Applications

Evaluate: tan 25°/cot 65°

Answer

tan 25°/cot 65° = tan 25°/cot(90° - 25°) = tan 25°/tan 25° = 1 Since cot 65° = cot(90° - 25°) = tan 25°

+14 more flashcards available

Practice All

Frequently Asked Questions

What are the important topics in Complementary Angles for ICSE Class 9 Mathematics?
Complementary Angles covers several key topics that are frequently asked in ICSE Class 9 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Complementary Angles — ICSE Class 9 Mathematics?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
How many flashcards are available for Complementary Angles?
There are 22 flashcards for Complementary Angles covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

Sources & Official References

Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.

For serious students

Get the full Complementary Angles chapter — for free.

Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for ICSE Class 9 Mathematics.