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Chapter 12 of 26
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Concurrent Lines

NIOS · Class 10 · Maths

Flashcards for Concurrent Lines — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.

45 questions20 flashcards4 concepts

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A diagram illustrating different ways two or more distinct lines can interact in a plane: intersecting lines, parallel lines, and concurrent lines.
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20 Flashcards
Card 1Angle Bisectors and Incentre

In triangle ABC, if the angle bisectors AD, BE, and CF meet at point I, find the inradius if the sides are 3 cm, 4 cm, and 5 cm.

Answer

Step 1: Check if it's a right triangle: 3² + 4² = 9 + 16 = 25 = 5². Yes, it's a right triangle. Step 2: For a right triangle with legs a, b and hypotenuse c, inradius r = (a + b - c)/2 Step 3: r = (3

Card 2Perpendicular Bisectors and Circumcentre

Find the circumradius of an equilateral triangle with side length 6 cm.

Answer

Step 1: For an equilateral triangle, circumradius R = a/√3 where a is the side length Step 2: R = 6/√3 = 6/√3 × √3/√3 = 6√3/3 = 2√3 cm Step 3: Alternative method using altitude: altitude h = (√3/2) ×

Card 3Medians and Centroid

In triangle ABC, G is the centroid and AG = 8 cm. Find the length of the median AD.

Answer

Step 1: Recall that centroid divides each median in the ratio 2:1 Step 2: AG:GD = 2:1, which means AG = (2/3) × AD Step 3: Given AG = 8 cm, so 8 = (2/3) × AD Step 4: AD = 8 × (3/2) = 12 cm Step 5: Ver

Card 4Special Properties

Prove that in an isosceles triangle ABC where AB = AC, the angle bisector from A is also the perpendicular bisector of BC.

Answer

Step 1: Let AD be the angle bisector of ∠BAC, meeting BC at D Step 2: In triangles ABD and ACD: - AB = AC (given) - ∠BAD = ∠CAD (AD bisects ∠A) - AD = AD (common side) Step 3: By SAS congruence, △ABD

Card 5Formula Applications

When do you use the formula for circumradius R = abc/(4K) where K is the area?

Answer

Use this formula when: 1. You know all three sides (a, b, c) of the triangle 2. You can calculate the area using Heron's formula or other methods 3. You need to find circumradius for any triangle type

Card 6Coordinate Geometry

Find the coordinates of the centroid of triangle with vertices A(2,3), B(4,7), and C(6,1).

Answer

Step 1: Centroid formula: G = ((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3) Step 2: Identify coordinates: A(2,3), B(4,7), C(6,1) Step 3: x-coordinate of centroid = (2+4+6)/3 = 12/3 = 4 Step 4: y-coordinate of centroid

Card 7Altitudes and Orthocentre

In triangle ABC, the altitudes are AD, BE, and CF. If triangle is obtuse at B, where is the orthocentre located?

Answer

Step 1: For an obtuse triangle, the orthocentre lies outside the triangle Step 2: Since ∠B is obtuse (>90°), the orthocentre H lies on the opposite side of BC from vertex A Step 3: To locate H: - Exte

Card 8Angle Bisectors and Incentre

Solve: Find the inradius of triangle with sides 8, 15, and 17 units.

Answer

Step 1: Check triangle type: 8² + 15² = 64 + 225 = 289 = 17². It's a right triangle. Step 2: For right triangle with legs a, b and hypotenuse c: r = (a + b - c)/2 Step 3: r = (8 + 15 - 17)/2 = 6/2 = 3

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Frequently Asked Questions

What are the important topics in Concurrent Lines for NIOS Class 10 Maths?
Concurrent Lines covers several key topics that are frequently asked in NIOS Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
How to score full marks in Concurrent Lines — NIOS Class 10 Maths?
Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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There are 20 flashcards for Concurrent Lines covering key definitions, formulas, and concepts. Use them daily for 10–15 minutes for best results.

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