Constructions

Answer

Step 1: Draw ray AC at acute angle to AB. Step 2: Mark 8 equal points C₁, C₂...C₈ on AC (3+5=8). Step 3: Join C₈ to B. Step 4: Through C₃, draw line parallel to C₈B meeting AB at D. Result: D divides …

Answer

Step 1: Draw AB = 6cm as base. Step 2: With A as center, radius 5cm, draw arc. Step 3: With B as center, radius 4cm, draw arc intersecting first arc at C. Step 4: Join AC and BC. Triangle ABC is const…

Answer

Step 1: Draw PQ = 5cm. Step 2: At Q, construct ∠PQX = 60° using compass. Step 3: With Q as center, radius 4cm, cut arc on QX at R. Step 4: Join PR. Triangle PQR is constructed with two sides and inclu…

Answer

Step 1: Draw BC = 5cm. Step 2: At B, construct ∠CBP = 45°. Step 3: At C, construct ∠BCQ = 60°. Step 4: Let BP and CQ meet at A. Triangle ABC is constructed with two angles and included side given.

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Step 1: Draw BC = 4cm. Step 2: At B, construct 90° angle (perpendicular line BP). Step 3: With C as center, radius 7cm, draw arc cutting BP at A. Step 4: Join AC. Right triangle ABC with hypotenuse AC…

Answer

Step 1: Draw XY = 12cm. Step 2: At X, construct ∠YXP = 15° (half of 30°). Step 3: At Y, construct ∠XYQ = 22.5° (half of 45°). Let XP, YQ meet at A. Step 4: Draw perpendicular bisector of XA meeting XY…

Answer

Step 1: Draw BC = 4cm. Step 2: At B, construct ∠CBK = 60°. Step 3: Cut BP = 8cm on BK. Step 4: Join CP. Step 5: Draw perpendicular bisector of CP meeting BP at A. Step 6: Join AC. Triangle ABC with su…

Answer

Step 1: Draw BC = 5cm. Step 2: At B, construct ∠CBP = 45°. Step 3: Cut BK = 2cm on BP. Step 4: Join CK. Step 5: Draw perpendicular bisector of CK meeting BP extended at A. Step 6: Join AC. Triangle AB…