Special Products And Factorization
NIOS · Class 10 · Maths
Flashcards for Special Products And Factorization — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.
Interactive on Super Tutor
Studying Special Products And Factorization? Get the full interactive chapter.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan — built for flashcards and more.
1,000+ Class 10 students started this chapter today
Super Tutor has 6+ illustrations like this for Special Products And Factorization alone — flashcards, concept maps, and step-by-step visuals.
See them allExpand: (3x + 4)²
Answer
Using formula (a + b)² = a² + 2ab + b² Step 1: Identify a = 3x, b = 4 Step 2: Apply formula → (3x)² + 2(3x)(4) + (4)² Step 3: Calculate → 9x² + 24x + 16 Answer: 9x² + 24x + 16…
Expand: (5a - 3b)²
Answer
Using formula (a - b)² = a² - 2ab + b² Step 1: Identify a = 5a, b = 3b Step 2: Apply formula → (5a)² - 2(5a)(3b) + (3b)² Step 3: Calculate → 25a² - 30ab + 9b² Answer: 25a² - 30ab + 9b²…
Calculate: 103² using special products
Answer
Write 103 = 100 + 3 Using (a + b)² = a² + 2ab + b² Step 1: (100 + 3)² = 100² + 2(100)(3) + 3² Step 2: = 10000 + 600 + 9 Step 3: = 10609 Answer: 10609…
Calculate: 97² using special products
Answer
Write 97 = 100 - 3 Using (a - b)² = a² - 2ab + b² Step 1: (100 - 3)² = 100² - 2(100)(3) + 3² Step 2: = 10000 - 600 + 9 Step 3: = 9409 Answer: 9409…
Expand: (2x + 5)(2x - 5)
Answer
Using formula (a + b)(a - b) = a² - b² Step 1: Identify a = 2x, b = 5 Step 2: Apply formula → (2x)² - (5)² Step 3: Calculate → 4x² - 25 Answer: 4x² - 25…
Calculate: 73 × 67 using special products
Answer
Write as (70 + 3)(70 - 3) Using (a + b)(a - b) = a² - b² Step 1: (70 + 3)(70 - 3) = 70² - 3² Step 2: = 4900 - 9 Step 3: = 4891 Answer: 4891…
Expand: (x + 3)(x + 7)
Answer
Using formula (x + a)(x + b) = x² + (a + b)x + ab Step 1: Identify a = 3, b = 7 Step 2: Sum: a + b = 3 + 7 = 10 Step 3: Product: ab = 3 × 7 = 21 Step 4: x² + 10x + 21 Answer: x² + 10x + 21…
Expand: (3x + 2)(2x + 5)
Answer
Using formula (ax + b)(cx + d) = acx² + (ad + bc)x + bd Step 1: a = 3, b = 2, c = 2, d = 5 Step 2: ac = 3 × 2 = 6 Step 3: ad + bc = 3 × 5 + 2 × 2 = 15 + 4 = 19 Step 4: bd = 2 × 5 = 10 Answer: 6x² + 19…
+12 more flashcards available
Practice AllFrequently Asked Questions
What are the important topics in Special Products And Factorization for NIOS Class 10 Maths?
How to score full marks in Special Products And Factorization — NIOS Class 10 Maths?
How many flashcards are available for Special Products And Factorization?
Sources & Official References
Content is aligned to the official syllabus. Refer to the board website for the latest curriculum.
More resources for Special Products And Factorization
Important Questions
Practice with board exam-style questions
Syllabus
What topics to cover
Revision Notes
Key points for last-minute revision
Study Plan
Step-by-step plan to ace this chapter
Formula Sheet
All formulas in one place
Chapter Summary
Understand the chapter at a glance
Practice Quiz
Test yourself with a quick quiz
Concept Maps
See how topics connect visually
For serious students
Get the full Special Products And Factorization chapter — for free.
Quizzes, flashcards, AI doubt-solver and a step-by-step study plan for NIOS Class 10 Maths.