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Chapter 13 of 26
Flashcards

Quadrilaterals

NIOS · Class 10 · Maths

Flashcards for Quadrilaterals — NIOS Class 10 Maths. Quick Q&A cards covering key concepts, definitions, and formulas.

40 questions20 flashcards5 concepts

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A labeled diagram of a general quadrilateral showing its sides, vertices, and diagonals.
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20 Flashcards
Card 1Basic Properties

Find the fourth angle of a quadrilateral if three angles are 85°, 95°, and 70°.

Answer

Step 1: Use angle sum property - sum of all angles in quadrilateral = 360° Step 2: Let fourth angle = x Step 3: 85° + 95° + 70° + x = 360° Step 4: 250° + x = 360° Step 5: x = 360° - 250° = 110° Answer

Card 2Parallelogram Properties

In parallelogram ABCD, if ∠A = 75°, find all other angles.

Answer

Step 1: In parallelogram, opposite angles are equal So ∠A = ∠C = 75° Step 2: Adjacent angles are supplementary (sum = 180°) ∠A + ∠B = 180° 75° + ∠B = 180° ∠B = 105° Step 3: ∠B = ∠D = 105° (opposite an

Card 3Rhombus Properties

Two adjacent angles of a rhombus are in ratio 2:3. Find all angles of the rhombus.

Answer

Step 1: Let adjacent angles be 2x and 3x Step 2: Adjacent angles in rhombus are supplementary 2x + 3x = 180° 5x = 180° x = 36° Step 3: The two adjacent angles are: 2x = 72° and 3x = 108° Step 4: Oppos

Card 4Mid-Point Theorem

When do you use the Mid-Point Theorem? Give the formula and solve: In triangle ABC, D and E are midpoints of AB and AC. If BC = 12 cm, find DE.

Answer

Use when: Line segment joins midpoints of two sides of a triangle Theorem: DE = ½BC and DE || BC Solution: Step 1: Given BC = 12 cm Step 2: D and E are midpoints of AB and AC Step 3: Apply mid-point t

Card 5Rectangle Properties

In rectangle PQRS, diagonal PR = 13 cm and PQ = 5 cm. Find the perimeter.

Answer

Step 1: In rectangle, opposite sides equal and all angles 90° Step 2: Use Pythagoras theorem in right triangle PQR PR² = PQ² + QR² 13² = 5² + QR² 169 = 25 + QR² QR² = 144 QR = 12 cm Step 3: PQ = RS =

Card 6Area Calculations

Find the area of parallelogram ABCD if base AB = 8 cm and corresponding height = 6 cm. If another side AD = 5 cm, find the height corresponding to AD.

Answer

Step 1: Area of parallelogram = base × height Area = AB × h₁ = 8 × 6 = 48 cm² Step 2: For same parallelogram with different base: Area = AD × h₂ 48 = 5 × h₂ h₂ = 48/5 = 9.6 cm Step 3: Verify: Both giv

Card 7Rhombus Properties

Prove that diagonals of a rhombus bisect each other at right angles. If one diagonal = 16 cm and other = 12 cm, find the side length.

Answer

Proof: Rhombus is parallelogram → diagonals bisect each other. All sides equal → diagonals perpendicular. Problem Solution: Step 1: Diagonals AC = 16 cm, BD = 12 cm Step 2: They bisect at O, so AO = 8

Card 8Square Properties

In square ABCD, if diagonal AC = 10√2 cm, find the side length and area.

Answer

Step 1: In square, diagonal = side × √2 Let side = a Diagonal = a√2 = 10√2 Step 2: Solve for side length: a√2 = 10√2 a = 10 cm Step 3: Area of square = side² Area = 10² = 100 cm² Step 4: Verify using

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What are the important topics in Quadrilaterals for NIOS Class 10 Maths?
Quadrilaterals covers several key topics that are frequently asked in NIOS Class 10 board exams. Focus on the core concepts listed on this page and practise related questions to build confidence.
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Start by understanding all key concepts. Practise previous year questions from this chapter. Revise formulas and definitions regularly. Use flashcards for quick revision before the exam.
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